Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn<\/p>\n\n\n\n
\u0110\u00f4\u0301i v\u01a1\u0301i s\u00f4\u0301 t\u01b0\u0323 nhi\u00ean, chu\u0301ng ta co\u0301 ca\u0301c phe\u0301p toa\u0300n c\u00f4\u0323ng, tr\u01b0\u0300, nh\u00e2n, chia. \u0110\u00f4\u0301i v\u01a1\u0301i s\u00f4\u0301 h\u01b0\u0303u ti\u0309 cu\u0303ng v\u00e2\u0323y. \u01a0\u0309 ba\u0300i vi\u00ea\u0301t tr\u01b0\u01a1\u0301c, chu\u0301ng ta \u0111a\u0303 ti\u0300m hi\u00ea\u0309u v\u00ea\u0300 kha\u0301i ni\u00ea\u0323m s\u00f4\u0301 h\u01b0\u0303u ti\u0309. V\u01a1\u0301i ba\u0300i vi\u00ea\u0301t na\u0300y, Vietlearn se\u0303 cu\u0300ng ca\u0301c ba\u0323n ho\u0323c sinh ti\u0300m hi\u00ea\u0309u ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 c\u00f4\u0323ng tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309. C\u00f4\u0323ng tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309 nh\u01b0 th\u00ea\u0301 na\u0300o? Ca\u0301c da\u0323ng ba\u0300i t\u00e2\u0323p co\u0301 kho\u0301 khong? T\u00e2\u0301t t\u00e2\u0300n t\u00e2\u0323t ly\u0301 thuy\u00ea\u0301t va\u0300 ba\u0300i t\u00e2\u0323p \u0111\u01b0\u01a1\u0323c Vietlearn t\u00f4\u0309ng h\u01a1\u0323p sau \u0111\u00e2y:<\/p>\n\n\n\n
Ly\u0301 thuy\u00ea\u0301t c\u00e2\u0300n nh\u01a1\u0301<\/p>\n\n\n\n
Phe\u0301p c\u00f4\u0323ng s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Phe\u0301p c\u00f4\u0323ng s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Ta co\u0301 2 s\u00f4\u0301 h\u01b0\u0303u ti\u0309 x va\u0300 y trong \u0111o\u0301:<\/p>\n\n\n\n
x = a\/b, y = c\/d (b va\u0300 d kha\u0301c 0 va\u0300 thu\u00f4\u0323c Z)<\/p>\n\n\n\n
x + y = a\/b + c\/d<\/p>\n\n\n\n
\u0110\u00ea\u0309 th\u01b0\u0323c hi\u00ea\u0323n phe\u0301p c\u00f4\u0323ng s\u00f4\u0301 h\u01b0\u0303u ti\u0309, ta th\u01b0\u0323c hi\u00ea\u0323n \u0111\u01b0a hai ph\u00e2n s\u00f4\u0301 v\u00ea\u0300 cu\u0300ng m\u00e2\u0303u s\u00f4\u0301. Go\u0323i m la\u0300 m\u00e2\u0303u s\u00f4\u0301 chung cu\u0309a hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309 x va\u0300 y. Sau \u0111o\u0301, ta th\u01b0\u0323c hi\u00ea\u0323n c\u00f4\u0323ng hai t\u01b0\u0309 s\u00f4\u0301. T\u00f4\u0301i gia\u0309n ph\u00e2n s\u00f4\u0301 (n\u00ea\u0301u ph\u00e2n s\u00f4\u0301 ch\u01b0a t\u00f4\u0301i gia\u0309n) \u0111\u00ea\u0309 \u0111\u01b0\u01a1\u0323c k\u00ea\u0301t qua\u0309 phe\u0301p c\u00f4\u0323ng.<\/p>\n\n\n\n
x + y = a\/b + c\/d = a1\/m + b1\/m = (a1 + b1) \/ m<\/p>\n\n\n\n
Vi\u0301 du\u0323: C\u00f4\u0323ng hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309 1\/2 + 2\/3<\/p>\n\n\n\n
Ta co\u0301: 1\/2 + 2\/3 = 3\/6 + 4\/6 = 7\/6<\/p>\n\n\n\n
Phe\u0301p tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Phe\u0301p tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Ta co\u0301 2 s\u00f4\u0301 h\u01b0\u0303u i\u0309 va\u0300 x va\u0300 y trong \u0111o\u0301:<\/p>\n\n\n\n
x = a\/b, y = c\/d (b va\u0300 d kha\u0301c 0 va\u0300 thu\u00f4\u0323c Z)<\/p>\n\n\n\n
x \u2013 y = a\/b \u2013 c\/d<\/p>\n\n\n\n
\u0110\u00ea\u0309 th\u01b0\u0323c hi\u00ea\u0323n phe\u0301p tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309, ta th\u01b0\u0323c hi\u00ea\u0323n \u0111\u01b0a hai ph\u00e2n s\u00f4\u0301 v\u00ea\u0300 cu\u0300ng m\u00e2\u0303u s\u00f4\u0301. Go\u0323i m la\u0300 m\u00e2\u0303u s\u00f4\u0301 chung cu\u0309a hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309 x va\u0300 y. Sau \u0111o\u0301, ta th\u01b0\u0323c hi\u00ea\u0323n tr\u01b0\u0300 hai t\u01b0\u0309 s\u00f4\u0301. T\u00f4\u0301i gia\u0309n ph\u00e2n s\u00f4\u0301 (n\u00ea\u0301u ph\u00e2n s\u00f4\u0301 ch\u01b0a t\u00f4\u0301i gia\u0309n) \u0111\u00ea\u0309 \u0111\u01b0\u01a1\u0323c k\u00ea\u0301t qua\u0309.<\/p>\n\n\n\n
x \u2013 y = a\/b \u2013 c\/d = a1\/m \u2013 b1\/m = (a1 \u2013 b1) \/ m<\/p>\n\n\n\n
Vi\u0301 du\u0323: Tr\u01b0\u0300 hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309 3\/5 \u2013 2\/4<\/p>\n\n\n\n
Ta co\u0301: 3\/5 \u2013 2\/4 = 12\/20 \u2013 10\/20 = 2\/20 = 1\/10<\/p>\n\n\n\n
Xem ngay: Ho\u0323c Toa\u0301n 7 cu\u0300ng Vietlearn: Phe\u0301p nh\u00e2n, chia s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Quy t\u0103\u0301c chuy\u00ea\u0309n v\u00ea\u0301, \u0111\u00f4\u0309i d\u00e2\u0301u<\/p>\n\n\n\n
Trong m\u00f4\u0323t \u0111\u0103\u0309ng th\u01b0\u0301c, khi chuy\u00ea\u0309n s\u00f4\u0301 ha\u0323ng t\u01b0\u0300 v\u00ea\u0301 na\u0300y sang v\u00ea\u0301 kia, ta pha\u0309i \u0111\u00f4\u0309i d\u00e2\u0301u s\u00f4\u0301 ha\u0323ng \u0111o\u0301.<\/p>\n\n\n\n
\u0110\u00f4\u0309i s\u00f4\u0301 h\u01b0\u0303u ti\u0309 d\u01b0\u01a1ng tha\u0300nh s\u00f4\u0301 h\u01b0\u0303u ti\u0309 \u00e2m.<\/p>\n\n\n\n
\u0110\u00f4\u0309i s\u00f4\u0301 h\u01b0\u0303u ti\u0309 \u00e2m tha\u0300nh s\u00f4\u0301 h\u01b0\u0303u ti\u0309 d\u01b0\u01a1ng.<\/p>\n\n\n\n
T\u00f4\u0309ng qua\u0301t: V\u01a1\u0301i mo\u0323i a, b, c thu\u00f4\u0323c Q ta co\u0301:<\/p>\n\n\n\n
a + b = c => a = c \u2013 b<\/p>\n\n\n\n
Vi\u0301 du\u0323: 1\/4 + 3\/4 = 1 => 1\/4 = 1 \u2013 3\/4<\/p>\n\n\n\n
Ba\u0300i t\u00e2\u0323p v\u00e2\u0323n du\u0323ng<\/p>\n\n\n\n
Ba\u0300i 1: Th\u01b0\u0323c hi\u00ea\u0323n ca\u0301c phe\u0301p c\u00f4\u0323ng, tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309:<\/p>\n\n\n\n
a. 1\/2 + 2\/5<\/p>\n\n\n\n
b. 2\/3 + 4\/7<\/p>\n\n\n\n
c. 3\/4 \u2013 1\/2<\/p>\n\n\n\n
d. 4\/5 \u2013 3\/4<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i<\/p>\n\n\n\n
a. 1\/2 + 2\/5 = 5\/10 + 4\/10 = 9\/10<\/p>\n\n\n\n
b. 2\/3 + 4\/7 = 14\/21 + 12\/21 = 16\/21<\/p>\n\n\n\n
c. 3\/4 -1\/2 = 3\/4 -2\/4 = 1\/4<\/p>\n\n\n\n
d. 4\/5 -3\/4 = 16\/20 -15\/20 = 1\/20<\/p>\n\n\n\n
Ba\u0300i 2: Ti\u0300m s\u00f4\u0301 h\u01b0u ti\u0309 x tho\u0309a ma\u0303n:<\/p>\n\n\n\n
a. x \u2013 3\/4 = 5\/12<\/p>\n\n\n\n
b. 4\/5 \u2013 x = 7\/20<\/p>\n\n\n\n
c. 9\/4 + x = 12\/8<\/p>\n\n\n\n
d. x + 3\/7 = 5\/21<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i<\/p>\n\n\n\n
a. x \u2013 3\/4 = 5\/12<\/p>\n\n\n\n
=> x = 5\/12 + 3\/4<\/p>\n\n\n\n
=> x = 5\/12 + 9\/12<\/p>\n\n\n\n
=> x = 14\/12 = 7\/6<\/p>\n\n\n\n
b. 4\/5 \u2013 x = 7\/20<\/p>\n\n\n\n
=> x = 4\/5 \u2013 7\/20<\/p>\n\n\n\n
=> x = 16\/20 \u2013 7\/20<\/p>\n\n\n\n
=> x = 9\/20<\/p>\n\n\n\n
c. 9\/4 + x = 12\/8<\/p>\n\n\n\n
=> x = 12\/8 \u2013 9\/4<\/p>\n\n\n\n
=> x = 12\/8 \u2013 18\/8<\/p>\n\n\n\n
=> x = -6\/8 = -3\/4<\/p>\n\n\n\n
d. x + 3\/7 = 5\/21<\/p>\n\n\n\n
=> x = 5\/21 \u2013 3\/7<\/p>\n\n\n\n
=> x = 5\/21 \u2013 9\/21<\/p>\n\n\n\n
=> x = -4\/21<\/p>\n\n\n\n
Ba\u0300i 3: Ti\u0301nh gia\u0301 tri\u0323 bi\u00ea\u0309u th\u01b0\u0301c:<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i<\/p>\n\n\n\n
\u0110\u00f4\u0301i v\u01a1\u0301i ba\u0300i Toa\u0301n na\u0300y, ta co\u0301 th\u00ea\u0309 gia\u0309i theo hai ca\u0301ch:<\/p>\n\n\n\n
Ca\u0301ch 1:<\/p>\n\n\n\n
Ca\u0301ch 2:<\/p>\n\n\n\n
Ba\u0300i t\u00e2\u0323p v\u00e2\u0323n du\u0323ng cao<\/p>\n\n\n\n
Ba\u0300i 4: Trong v\u01b0\u01a1\u0300n c\u00e2y cu\u0309a ba\u0301c An co\u0301 46 c\u00e2y g\u00f4\u0300m c\u00e2y ta\u0301o, c\u00e2y xoa\u0300i, c\u00e2y \u00f4\u0309i. Trong \u0111o\u0301 co\u0301 s\u00f4\u0301 c\u00e2y xoa\u0300i la\u0300 28\/4 c\u00e2y. 36\/3 la\u0300 s\u00f4\u0301 c\u00e2y \u00f4\u0309i co\u0301 trong v\u01b0\u01a1\u0300n. Ho\u0309i trong v\u01b0\u01a1\u0300n cu\u0309a ba\u0301c An co\u0301 bao nhi\u00eau c\u00e2y ta\u0301o?<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i:<\/p>\n\n\n\n
Trong v\u01b0\u01a1\u0300n cu\u0309a ba\u0301c An co\u0301 28\/4 c\u00e2y xoa\u0300i t\u01b0\u0301c la\u0300 co\u0301 7 c\u00e2y xoa\u0300i.<\/p>\n\n\n\n
Trong v\u01b0\u01a1\u0300n cu\u0309a ba\u0301c An co\u0301 36\/3 c\u00e2y xoa\u0300i t\u01b0\u0301c la\u0300 co\u0301 12 c\u00e2y xoa\u0300i.<\/p>\n\n\n\n
S\u00f4\u0301 c\u00e2y ta\u0301o co\u0301 trong v\u01b0\u01a1\u0300n cu\u0309a ba\u0301c An la\u0300 46 \u2013 7 -12 = 27 c\u00e2y<\/p>\n\n\n\n
Ba\u0300i 5: Vi\u00ea\u0301t s\u00f4\u0301 h\u01b0\u0303u ti\u0309 7\/12 tha\u0300nh ca\u0301c da\u0323ng sau \u0111\u00e2y:<\/p>\n\n\n\n
a. 7\/12 la\u0300 t\u00f4\u0309ng hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309 d\u01b0\u01a1ng.<\/p>\n\n\n\n
b. 7\/12 la\u0300 hi\u00ea\u0323u cu\u0309a m\u00f4\u0323t s\u00f4\u0301 h\u01b0\u0303u ti\u0309 \u00e2m va\u0300 m\u00f4\u0323t s\u00f4\u0301 h\u01b0\u0303u ti\u0309 d\u01b0\u01a1ng.<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i:<\/p>\n\n\n\n
a. 7\/12 = 1\/12 + 6\/12 = 2\/12 + 5\/12 = 1\/6 + 5\/12 = 3\/12 + 4\/12 = 1\/4 + 1\/3<\/p>\n\n\n\n
b. 7\/12 = 9\/12 \u2013 2\/12 = 3\/4 \u2013 1\/6 = 6\/8 \u2013 2\/12 = 10\/12 \u2013 3\/12 = 5\/6 \u2013 1\/4<\/p>\n\n\n\n
H\u1ecdc t\u1ed1t l\u1edbp 7<\/p>\n\n\n\n
L\u01b0u y\u0301 \u0111\u00ea\u0309 la\u0300m t\u00f4\u0301t ca\u0301c da\u0323ng ba\u0300i v\u00ea\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
S\u00f4\u0301 h\u01b0\u0303u ti\u0309 la\u0300 ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c m\u01a1\u0301i n\u00ean nhi\u00ea\u0300u ba\u0323n ca\u0309m th\u00e2\u0301y kha\u0301 kho\u0301 kh\u0103n. Tuy nhi\u00ean, \u0111\u00e2y la\u0300 ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c c\u01a1 ba\u0309n, mang ti\u0301nh ch\u00e2\u0301t n\u00ea\u0300n ta\u0309ng n\u00ean ca\u0301c ba\u0323n ho\u0323c sinh c\u00e2\u0300n pha\u0309i n\u0103\u0301m v\u01b0\u0303ng. Vietlearn nh\u0103\u0301c ba\u0323n m\u00f4\u0323t s\u00f4\u0301 l\u01b0u y\u0301 khi la\u0300m ca\u0301c da\u0323ng ba\u0300i c\u00f4\u0323ng tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309 no\u0301i ri\u00eang, da\u0323ng ba\u0300i v\u00ea\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309 no\u0301i chung.<\/p>\n\n\n\n
\u0110\u00ea\u0309 y\u0301 ph\u00e2\u0300n m\u00e2\u0303u s\u00f4\u0301 b\u0103\u0301t bu\u00f4\u0323c pha\u0309i kha\u0301c 0. S\u00f4\u0301 h\u01b0\u0303u ti\u0309 co\u0301 m\u00e2\u0303u s\u00f4\u0301 la\u0300 0 la\u0300 v\u00f4 nghi\u0303a.<\/p>\n\n\n\n
Chu\u0301 y\u0301 tho\u0309a ma\u0303n ca\u0301c \u0111i\u00ea\u0300u ki\u00ea\u0323n \u0111\u00ea\u0300 ba\u0300i nh\u01b0: l\u01a1\u0301n h\u01a1n, nho\u0309 h\u01a1n, trong khoa\u0309ng,\u2026<\/p>\n\n\n\n
\u0110\u01b0a v\u00ea\u0300 ti\u0300m m\u00e2\u0303u s\u00f4\u0301 chung \u0111\u00ea\u0309 d\u00ea\u0303 da\u0300ng ti\u0301nh toa\u0301n.<\/p>\n\n\n\n
K\u00ea\u0301t qua\u0309 c\u00e2\u0300n \u0111\u01b0\u01a1\u0323c th\u00ea\u0309 hi\u00ea\u0323n theo ph\u00e2n s\u00f4\u0301 t\u00f4\u0301i gia\u0309n la\u0300 t\u00f4\u0301t nh\u00e2\u0301t. N\u00ean ru\u0301t go\u0323n ph\u00e2n s\u00f4\u0301.<\/p>\n\n\n\n
Chu\u0301 y\u0301 d\u00e2\u0301u cu\u0309a ca\u0301c s\u00f4\u0301. Nh\u01a1\u0303 ky\u0303 nguy\u00ean t\u0103\u0301c \u201cchuy\u00ea\u0309n v\u00ea\u0301 pha\u0309i \u0111\u00f4\u0309i d\u00e2\u0301u\u201d.<\/p>\n\n\n\n
Vi\u0300 sao c\u00e2\u0300n ho\u0323c t\u00f4\u0301t Toa\u0301n ho\u0323c?<\/p>\n\n\n\n
B\u1eaft \u0111\u1ea7u t\u1eeb khi ch\u00fang ta v\u00e0o l\u1edbp m\u1ed9t ti\u1ec3u ho\u0323c, r\u00f4\u0300i khi ho\u0323c c\u00e2\u0301p THCS, l\u00ean \u0111\u00ea\u0301n c\u00e2\u0301p THPT trong su\u00f4\u0301t th\u1eddi gian 12 n\u0103m, h\u00e0ng n\u0103m \u0111\u1ec1u ph\u1ea3i h\u1ecdc to\u00e1n h\u1ecdc. Trong sa\u0301ch gia\u0301o khoa ch\u01b0\u01a1ng tri\u0300nh gia\u0301o du\u0323c ti\u1ec3u h\u1ecdc v\u00e0 ph\u1ed5 th\u00f4ng c\u01a1 s\u1edf, to\u00e1n h\u1ecdc la\u0300 m\u00f4\u0323t trong 3 m\u00f4n chi\u0301nh b\u00ean ca\u0323nh ng\u1eef v\u0103n va\u0300 ngo\u1ea1i ng\u1eef. C\u00e1c n\u01b0\u1edbc tr\u00ean th\u1ebf gi\u1edbi \u0111\u1ec1u nh\u01b0 v\u1eady. Ca\u0301c th\u00e2\u0300y c\u00f4 hay b\u00f4\u0301 me\u0323 chu\u0301ng ta \u0111\u00ea\u0300u nh\u00e2\u0301n ma\u0323nh vi\u00ea\u0323c chu\u0301ng ta pha\u0309i tru\u0301 t\u00e2m, da\u0300nh nhi\u00ea\u0300u th\u01a1\u0300i gian cho m\u00f4n ho\u0323c na\u0300y. Kh\u00f4ng bi\u1ebft b\u1ea1n \u0111\u00e3 ngh\u0129 \u0111\u1ebfn v\u00ec sao ph\u1ea3i h\u1ecdc to\u00e1n h\u1ecdc ch\u01b0a, m\u00e0 c\u00f2n ph\u1ea3i h\u1ecdc t\u1ed1t to\u00e1n h\u1ecdc n\u1eefa? c\u00f4\u0323ng tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Ly\u0301 gia\u0309i khoa ho\u0323c<\/p>\n\n\n\n
Th\u1ee9 nh\u1ea5t, to\u00e1n h\u1ecdc c\u0169ng gi\u1ed1ng nh\u01b0 ng\u1eef v\u0103n, ngo\u1ea1i ng\u1eef, l\u00e0 m\u1ed9t lo\u1ea1i ng\u00f4n ng\u1eef. Toa\u0301n ho\u0323c l\u00e0 ng\u00f4n ng\u1eef c\u1ee7a khoa h\u1ecdc. Toa\u0301n ho\u0323c s\u1eed d\u1ee5ng c\u00e1c lo\u1ea1i c\u00f4ng c\u1ee5 nh\u01b0 ch\u1eef s\u1ed1, k\u00fd hi\u1ec7u, c\u00f4ng th\u1ee9c, h\u00ecnh t\u01b0\u1ee3ng, kh\u00e1i ni\u1ec7m, \u0111\u1ecbnh l\u00ed v..v.. \u0111\u00ea\u0309 bi\u1ec3u \u0111\u1ea1t gi\u1ea3n l\u01b0\u1ee3c m\u00e0 ch\u00ednh x\u00e1c ca\u0301c m\u00f4\u0301i quan h\u00ea\u0323. Ca\u0301c m\u00f4\u0301i quan h\u00ea\u0323 \u01a1\u0309 \u0111\u00e2y la\u0300: quan h\u1ec7 gi\u1eefa v\u1ea1n v\u1eadt tr\u00ean th\u1ebf gi\u1edbi, quan h\u1ec7 v\u1ecb tr\u00ed trong kh\u00f4ng gian,\u2026 \u0111\u1ed1i v\u1edbi vi\u1ec7c nh\u00e2n lo\u1ea1i nh\u1eadn th\u1ee9c th\u1ebf gi\u1edbi. Kh\u00f4ng hi\u1ec3u to\u00e1n h\u1ecdc, ch\u00ednh l\u00e0 kh\u00f4ng th\u1ec3 l\u00ed gi\u1ea3i khoa h\u1ecdc. c\u00f4\u0323ng tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
B\u00f4\u0300i d\u01b0\u01a1\u0303ng t\u01b0 duy<\/p>\n\n\n\n
Th\u1ee9 hai, To\u00e1n h\u1ecdc gi\u00fap b\u1ed3i d\u01b0\u1ee1ng t\u01b0 duy l\u00ed t\u00ednh. Ta th\u00e2\u0301y ng\u1eef v\u0103n c\u00f3 th\u1ec3 d\u00f9ng \u0111\u1ec3 bi\u1ec3u th\u1ecb t\u00ecnh c\u1ea3m, nguy\u1ec7n v\u1ecdng, \u00fd ch\u00ed. To\u00e1n h\u1ecdc ch\u1ee7 y\u1ebfu d\u00f9ng \u0111\u1ec3 ti\u1ebfn h\u00e0nh t\u01b0 duy l\u00ed t\u00ednh nh\u01b0 kh\u00e1i qu\u00e1t, tr\u1eebu t\u01b0\u1ee3ng, suy lu\u00e2\u0323n\u2026 To\u00e1n h\u1ecdc nghi\u00eam kh\u1eafc ch\u00ednh x\u00e1c. Tr\u01b0\u1edbc nay kh\u00f4ng h\u00e0m h\u1ed3. Trong Toa\u0301n ho\u0323c mo\u0323i th\u01b0\u0301 \u0111\u00ea\u0300u ro\u0303 ra\u0300ng. Vi\u1ec7c gi\u00e1o d\u1ee5c kh\u1ea3 n\u0103ng t\u01b0 duy cho con ng\u01b0\u1eddi cu\u0303ng v\u00e2\u0323y. Gia\u0301o du\u0323c t\u01b0 duy r\u00e2\u0301t c\u00e2\u0300n thi\u00ea\u0301t va\u0300 kh\u00f4ng th\u1ec3 thi\u1ebfu \u0111\u01b0\u1ee3c.<\/p>\n\n\n\n
Toa\u0301n ho\u0323c \u01a1\u0309 xung quanh ta<\/p>\n\n\n\n
Th\u1ee9 ba, to\u00e1n h\u1ecdc xu\u1ea5t hi\u1ec7n \u1edf m\u1ecdi l\u0129nh v\u1ef1c t\u01b0\u0300 \u0111\u01a1n gia\u0309n \u0111\u00ea\u0301n vi\u0303 \u0111a\u0323i. Ta du\u0300ng Toa\u0301n ho\u0323c \u0111\u00ea\u0309 mua \u0111\u1ed3 tr\u00ean ph\u1ed1, \u0111i ch\u01a1\u0323,\u2026 Ca\u0301c pha\u0301t minh vi\u0303 \u0111a\u0323i \u0111\u00ea\u0300u b\u0103\u0301t ngu\u00f4\u0300n t\u01b0\u0300 Toa\u0301n nh\u01b0: thi\u1ebft k\u1ebf<\/a> m\u00e1y bay t\u00ean l\u1eeda, \u0111i\u1ec1u khi\u1ec3n v\u1eadn h\u00e0nh v\u1ec7 tinh,\u2026 T\u1ea5t c\u1ea3 \u0111\u1ec1u kh\u00f4ng th\u1ec3 t\u00e1ch r\u1eddi to\u00e1n h\u1ecdc \u0111\u01b0\u1ee3c. S\u1ef1 cao th\u1ea5p v\u1ec1 tr\u00ecnh \u0111\u1ed9 to\u00e1n h\u1ecdc c\u1ee7a m\u1ed9t qu\u1ed1c gia cu\u0303ng la\u0300 th\u01b0\u01a1\u0301c \u0111o ph\u1ea3n \u00e1nh \u0111\u01b0\u1ee3c qu\u1ed1c gia \u0111\u00f3 c\u00f3 c\u01b0\u1eddng th\u1ecbnh hay kh\u00f4ng.<\/p>\n\n\n\n L\u01a1\u0300i k\u00ea\u0301t<\/p>\n\n\n\n Tr\u00ean la\u0300 nh\u01b0\u0303ng ki\u00ea\u0301n th\u01b0\u0301c, ba\u0300i t\u00e2\u0323p va\u0300 l\u01b0u y\u0301 cu\u0309a Vietlearn v\u00ea\u0300 c\u00f4\u0323ng tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309.Vietlearn hy vo\u0323ng ba\u0300i vi\u00ea\u0301t na\u0300y \u0111a\u0303 cung c\u00e2\u0301p th\u00f4ng tin b\u00f4\u0309 i\u0301ch cho ba\u0323n \u0111o\u0323c. Truy c\u00e2\u0323p Website cu\u0309a Vietlearn \u0111\u00ea\u0309 c\u00e2\u0323p nh\u00e2\u0323t nhi\u00ea\u0300u th\u00f4ng tin thu\u0301 vi\u0323.<\/p>\n\n\n\n <\/p>\n\n\n\n Ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 T\u00e2\u0323p h\u01a1\u0323p Q ca\u0301c s\u00f4\u0301 h\u01b0\u0303u ti\u0309 \u2013 Gi\u1ecfi to\u00e1n l<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":" Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn \u0110\u00f4\u0301i v\u01a1\u0301i s\u00f4\u0301 t\u01b0\u0323 nhi\u00ean, chu\u0301ng ta co\u0301 ca\u0301c phe\u0301p toa\u0300n c\u00f4\u0323ng, tr\u01b0\u0300, nh\u00e2n, chia. \u0110\u00f4\u0301i v\u01a1\u0301i s\u00f4\u0301 h\u01b0\u0303u ti\u0309 cu\u0303ng v\u00e2\u0323y. \u01a0\u0309 ba\u0300i vi\u00ea\u0301t tr\u01b0\u01a1\u0301c, chu\u0301ng ta \u0111a\u0303 ti\u0300m hi\u00ea\u0309u v\u00ea\u0300 kha\u0301i ni\u00ea\u0323m s\u00f4\u0301 h\u01b0\u0303u ti\u0309. V\u01a1\u0301i ba\u0300i vi\u00ea\u0301t na\u0300y, Vietlearn se\u0303 cu\u0300ng ca\u0301c ba\u0323n ho\u0323c sinh ti\u0300m […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[9,4],"tags":[],"class_list":["post-2645","post","type-post","status-publish","format-standard","hentry","category-toan-hoc","category-trung-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2645","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=2645"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2645\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=2645"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=2645"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=2645"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}