{"id":2653,"date":"2021-10-14T21:17:34","date_gmt":"2021-10-14T14:17:34","guid":{"rendered":"https:\/\/www.vietlearn.org\/post\/?p=2653"},"modified":"2021-10-14T22:11:10","modified_gmt":"2021-10-14T15:11:10","slug":"tinh-chat-cu%cc%89a-da%cc%83y-ti%cc%89-so-bang-nhau-ho%cc%a3c-toan-7-cung-vietlearn","status":"publish","type":"post","link":"https:\/\/www.vietlearn.org\/kien-thuc\/tinh-chat-cu%cc%89a-da%cc%83y-ti%cc%89-so-bang-nhau-ho%cc%a3c-toan-7-cung-vietlearn\/","title":{"rendered":"Ti\u0301nh ch\u00e2\u0301t cu\u0309a da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau \u2013 Ho\u0323c Toa\u0301n 7 cu\u0300ng Vietlearn"},"content":{"rendered":"\n

Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn<\/p>\n\n\n\n

Trong ba\u0300i vi\u00ea\u0301t tr\u01b0\u01a1\u0301c, Vietlearn \u0111a\u0303 cu\u0300ng ca\u0301c ba\u0323n ho\u0323c sinh ti\u0300m hi\u00ea\u0309u ca\u0301c ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 lu\u0303y th\u01b0\u0300a, ti\u0309 l\u00ea\u0323 th\u01b0\u0301c. Trong ba\u0300i vi\u00ea\u0301t na\u0300y, Vietlearn cu\u0300ng ca\u0301c ba\u0323n ti\u0300m hi\u00ea\u0309u ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c m\u01a1\u0301i. \u0110o\u0301 la\u0300 ti\u0301nh ch\u00e2\u0301t cu\u0309a da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau. Ti\u0301nh ch\u00e2\u0301t da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau la\u0300 m\u00f4\u0323t ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c c\u00e2\u0300n n\u0103\u0301m ch\u0103\u0301c trong ch\u01b0\u01a1ng tri\u0300nh Toa\u0301n 7. Ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c na\u0300y y\u00eau c\u00e2\u0300u ca\u0301c ba\u0323n ho\u0323c sinh re\u0300n luy\u00ea\u0323n ky\u0303 n\u0103ng v\u00e2\u0323n du\u0323ng \u0111\u00ea\u0309 la\u0300m ca\u0301c da\u0323ng toa\u0301n chia ti\u0309 l\u00ea\u0323.<\/p>\n\n\n\n

T\u00f4\u0309ng quan ki\u00ea\u0301n th\u01b0\u0301c<\/p>\n\n\n\n

Ti\u0301nh ch\u00e2\u0301t cu\u0309a da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau<\/p>\n\n\n\n

Ta co\u0301 ti\u0309 l\u00ea\u0323 th\u01b0\u0301c: a\/b = c\/d = k (1)<\/p>\n\n\n\n

=> k = a x b ; c = k x d<\/p>\n\n\n\n

Ta co\u0301:<\/p>\n\n\n\n

(a + c) : (b +d) = (k + b) x (k +d) \/ (b + d) = k.(b + d) \/ (b + d) = k (2) (b + d kha\u0301c 0)<\/p>\n\n\n\n

(a \u2013 c) : (b \u2013 d) = (k \u2013 b) x (k \u2013 d) \/ (b \u2013 d) = k.(b \u2013 d) \/ (b \u2013 d) = k (3) (b + d kha\u0301c 0)<\/p>\n\n\n\n

T\u01b0\u0300 (1), (2) va\u0300 (3), ta co\u0301 k\u00ea\u0301t lu\u00e2\u0323n:<\/p>\n\n\n\n

a\/b = c\/d = (a + b) \/ (c + d) = (a \u2013 b) \/ (c \u2013 d) trong \u0111o\u0301 b kha\u0301c d va\u0300 b kha\u0301c -d)<\/p>\n\n\n\n

a\/b = c\/d = e\/f = (a + c + e) \/ (b + d +f) = (a \u2013 c + e) \/ (b \u2013 d + f)<\/p>\n\n\n\n

Vi\u0301 du\u0323 minh ho\u0323a ti\u0301nh ch\u00e2\u0301t da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau:<\/p>\n\n\n\n

Ta co\u0301: 4\/6 = 2\/3 => 4\/6 = 2\/3 = (4 +2) \/ (6 + 3) = (4 \u2013 2) \/ (6 \u2013 3) = 2\/3<\/p>\n\n\n\n

4\/3 = 0.4\/0.3 = 16\/12 => 4\/3 = 0.4\/0.3 = 16\/12 = (4 \u2013 0.4 + 16) \/ (3 \u2013 0.3 + 12) = 19.6\/14.7<\/p>\n\n\n\n

L\u01b0u y\u0301<\/p>\n\n\n\n

Ca\u0301c s\u00f4\u0301 a , b ,c ti\u0309 l\u00ea\u0323 v\u01a1\u0301i d, e, f ta bi\u00ea\u0309u di\u00ea\u0303n nh\u01b0 sau: a\/d = b\/e = c\/f<\/p>\n\n\n\n

Ho\u0103\u0323c bi\u00ea\u0309u di\u00ea\u0303n d\u01b0\u01a1\u0301i da\u0323ng kha\u0301c: a : d : b = e : c : f<\/p>\n\n\n\n

Xem ngay: Ho\u0323c Toa\u0301n 7 cu\u0300ng Vietlearn: Nh\u01b0\u0303ng \u0111i\u00ea\u0300u c\u00e2\u0300n bi\u00ea\u0301t v\u00ea\u0300 ti\u0309 l\u00ea\u0323 th\u01b0\u0301c<\/p>\n\n\n\n

Ba\u0300i t\u00e2\u0323p v\u00e2\u0323n du\u0323ng<\/p>\n\n\n\n

Ba\u0300i 1: Ti\u0300m x va\u0300 y bi\u00ea\u0301t:<\/p>\n\n\n\n

a. x\/y = 17\/3 va\u0300 x + y = 60<\/p>\n\n\n\n

b. x\/19 = y\/21 va\u0300 2x \u2013 y = 34<\/p>\n\n\n\n

c. x^2\/9 = y^2\/16 va\u0300 x^2 + y^2 = 100<\/p>\n\n\n\n

L\u01a1\u0300i gia\u0309i:<\/p>\n\n\n\n

a\/ Ta co\u0301: x\/y = 17\/3<\/p>\n\n\n\n

A\u0301p du\u0323ng ti\u0301nh ch\u00e2\u0301t da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau:<\/p>\n\n\n\n

x\/17 = y\/3 = (x + y) \/ (17 +3) = 60\/20 = 3<\/p>\n\n\n\n

Do \u0111o\u0301:<\/p>\n\n\n\n

x\/17 = 3 => x = 17 x 3 = 51<\/p>\n\n\n\n

y\/3 = 3 => y = 9<\/p>\n\n\n\n

V\u00e2\u0323y x = 51, y = 9<\/p>\n\n\n\n

b. x\/19 = y\/21<\/p>\n\n\n\n

A\u0301p du\u0323ng ti\u0301nh ch\u00e2\u0301t da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau:<\/p>\n\n\n\n

x\/19 = y\/21 => 2x\/38 = y\/21 = (2x -y) \/ (38 \u2013 21) = 34 \/17 = 2<\/p>\n\n\n\n

Do \u0111o\u0301:<\/p>\n\n\n\n

x\/19 = 2 => x = 38<\/p>\n\n\n\n

y\/21 = 2 => y = 42<\/p>\n\n\n\n

c. x^2\/9 = y^2\/16<\/p>\n\n\n\n

A\u0301p du\u0323ng ti\u0301nh ch\u00e2\u0301t da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau:<\/p>\n\n\n\n

x^2\/9 = y^2\/16 = (x^2 + y^2) \/ (9 + 16) = 100\/25 = 4<\/p>\n\n\n\n

Do \u0111o\u0301:<\/p>\n\n\n\n

x^2\/9 = 4 => x^2 = 36 => x = 6 ho\u0103\u0323c x = -6<\/p>\n\n\n\n

y^2\/16 = 4 => y^2 = 64 => y = 8 ho\u0103\u0323c y = -8<\/p>\n\n\n\n

V\u00e2\u0323y ta co\u0301 4 c\u0103\u0323p gia\u0301 tri\u0323 (x, y) la\u0300 (6 , 8); (-6, 8); (6, -8); (-6, -8)<\/p>\n\n\n\n

Ba\u0300i 2: Ba ba\u0323n An, Linh va\u0300 Ha\u0309i co\u0301 s\u00f4\u0301 \u0111i\u00ea\u0309m 10 ti\u0309 l\u00ea\u0323 v\u01a1\u0301i 2,3 va\u0300 4. Bi\u00ea\u0301t r\u0103\u0300ng t\u00f4\u0309ng s\u00f4\u0301 \u0111i\u00ea\u0309m 10 cu\u0309a An va\u0300 Ha\u0309i l\u01a1\u0301n h\u01a1n Linh la\u0300 6 \u0111i\u00ea\u0309m 10. Ho\u0309i m\u00f4\u0303i ba\u0323n co\u0301 bao nhi\u00eau \u0111i\u00ea\u0309m 10?<\/p>\n\n\n\n

L\u01a1\u0300i gia\u0309i:<\/p>\n\n\n\n

Go\u0323i a, b, c l\u00e2\u0300n l\u01b0\u01a1\u0323t la\u0300 s\u00f4\u0301 \u0111i\u00ea\u0309m 10 cu\u0309a 3 ba\u0323n An, Linh va\u0300 Ha\u0309i.<\/p>\n\n\n\n

Ta co\u0301: a\/2 = b\/3 = c\/4<\/p>\n\n\n\n

Vi\u0300 t\u00f4\u0309ng s\u00f4\u0301 \u0111i\u00ea\u0309m 10 cu\u0309a ba\u0323n An va\u0300 Ha\u0309i l\u01a1\u0301n h\u01a1n s\u00f4\u0301 \u0111i\u00ea\u0309m 10 cu\u0309a ba\u0323n Linh la\u0300 6 \u0111i\u00ea\u0309m. A\u0301p du\u0323ng ti\u0301nh ch\u00e2\u0301t da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau, ta co\u0301:<\/p>\n\n\n\n

a\/2 = b\/3 = c\/4 = (a + b \u2013 c) : (2 + 3 \u2013 4) = 6\/3 = 2<\/p>\n\n\n\n

Do \u0111o\u0301:<\/p>\n\n\n\n

a\/2 = 2 => a = 4<\/p>\n\n\n\n

b\/3 = 2 => b = 6<\/p>\n\n\n\n

c\/4 = 2 => c = 8<\/p>\n\n\n\n

V\u00e2\u0323y ba\u0323n An co\u0301 4 \u0111i\u00ea\u0309m 10, ba\u0323n Linh co\u0301 6 \u0111i\u00ea\u0309m 10, ba\u0323n Ha\u0309i co\u0301 8 \u0111i\u00ea\u0309m 10.<\/p>\n\n\n\n

Ba\u0300i 3: Ti\u0309 s\u00f4\u0301 cu\u0309a a va\u0300 b la\u0300 2 va\u0300 3 . N\u00ea\u0301u th\u00eam 1 va\u0300 2 va\u0300o a va\u0300 b thi\u0300 ti\u0309 s\u00f4\u0301 cu\u0309a a va\u0300 b la\u0300 11va\u0300 15. Ti\u0300m a va\u0300 b.<\/p>\n\n\n\n

Ba\u0300i 4: M\u00f4\u0323t b\u00ea\u0309 n\u01b0\u01a1\u0301c co\u0301 dung ti\u0301ch la\u0300 234 m\u00b3. Th\u01a1\u0300i gian \u0111\u00ea\u0309 b\u01a1m \u0111\u01b0\u01a1\u0323c 1m\u00b3 n\u01b0\u01a1\u0301c cu\u0309a b\u00ea\u0309 1 la\u0300 3 phu\u0301t. Th\u01a1\u0300i gian b\u00ea\u0309 2 b\u01a1m \u0111\u01b0\u01a1\u0323c 1m\u00b3 n\u01b0\u01a1\u0301c la\u0300 3 phu\u0301t. Th\u01a1\u0300i gian \u0111\u00ea\u0309 b\u01a1m \u0111\u01b0\u01a1\u0323c 1m\u00b3 n\u01b0\u01a1\u0301c cu\u0309a b\u00ea\u0309 3 la\u0300 5 phu\u0301t. Ho\u0309i m\u00f4\u0303i ma\u0301y b\u01a1m \u0111\u01b0\u01a1\u0323c bao nhi\u00eau m\u00b3 thi\u0300 \u0111\u00e2\u0300y b\u00ea\u0309?<\/p>\n\n\n\n

Ba\u0300i 5:Tam gia\u0301c ABC co\u0301 s\u1ed1 \u0111o ca\u0301c ca\u0323nh t\u1ec9 l\u1ec7 v\u1edbi 3, 5, 7. Chu vi c\u1ee7a tam gia\u0301c ABC l\u00e0 40,5 cm. Ti\u0301nh \u0111\u00f4\u0323 da\u0300i ca\u0301c ca\u0323nh AB, AC, BC.<\/p>\n\n\n\n

Ba\u0300i 6: Tam gia\u0301c ABC co\u0301 di\u00ea\u0323n ti\u0301ch la\u0300 27 cm\u00b2. Bi\u00ea\u0301t ti\u0309 s\u00f4\u0301 cu\u0309a ca\u0323nh huy\u00ea\u0300n va\u0300 \u0111\u01b0\u01a1\u0300ng cao cu\u0309a tam gia\u0301c b\u0103\u0300ng 1,5. Ti\u0301nh \u0111\u00f4\u0323 da\u0300i ca\u0323nh huy\u00ea\u0300n va\u0300 \u0111\u01b0\u01a1\u0300ng cao cu\u0309a tam gia\u0301c.<\/p>\n\n\n\n

Bi\u0301 m\u00e2\u0323t Toa\u0301n ho\u0323c<\/p>\n\n\n\n

Sau nh\u01b0\u0303ng gi\u01a1\u0300 phu\u0301t t\u00e2\u0323p trung ho\u0323c t\u00e2\u0323p, ha\u0303y cu\u0300ng Vietlearn gia\u0309i tri\u0301 v\u01a1\u0301i chuy\u00ean mu\u0323c bi\u0301 m\u00e2\u0323t Toa\u0301n ho\u0323c. Ta\u0323i \u0111\u00e2y Vietlearn se\u0303 b\u00e2\u0323t mi\u0301 cho ba\u0323n nh\u01b0\u0303ng \u0111i\u00ea\u0300u thu\u0301 vi\u0323 ma\u0300 chi\u0309 Toa\u0301n ho\u0323c m\u01a1\u0301i co\u0301.<\/p>\n\n\n\n

Y\u0301 nghi\u0303a cu\u0309a con s\u00f4\u0301 0<\/p>\n\n\n\n

T\u01b0\u0300 khi b\u0103\u0301t \u0111\u00e2\u0300u la\u0300m quen v\u01a1\u0301i Toa\u0301n ho\u0323c, s\u00f4\u0301 0 la\u0300 s\u00f4\u0301 \u0111\u00e2\u0300u ti\u00ean ma\u0300 ai trong chu\u0301ng ta cu\u0303ng bi\u00ea\u0301t t\u01a1\u0301i. Y\u0301 nghi\u0303a cu\u0309a s\u00f4\u0301 0 la\u0300 gi\u0300? Ca\u0301c y\u0301 nghi\u0303a cu\u0309a s\u00f4\u0301 0:<\/p>\n\n\n\n

Ba\u0323n \u0111\u00ea\u0301m s\u00f4\u0301 ba\u0301nh trong h\u00f4\u0323p ba\u0301nh 1 la\u0300 co\u0301 1 ca\u0301i ba\u0301nh, 2 la\u0300 co\u0301 2 ca\u0301i ba\u0301nh, 0 co\u0301 nghi\u0303a la\u0300 ch\u0103\u0309ng co\u0301 ca\u0301i ba\u0301nh na\u0300o h\u00ea\u0301t. Trong phe\u0301p ti\u0301nh 9 \u2013 9 ta \u0111\u01b0\u01a1\u0323c k\u00ea\u0301t qua\u0309 b\u0103\u0300ng 0 nghi\u0303a la\u0300 tr\u01b0\u0300 h\u00ea\u0301t sa\u0323ch r\u00f4\u0300i. 0 chi\u0301nh la\u0300 kh\u00f4ng co\u0301 gi\u0300.<\/p>\n\n\n\n

0 chi\u0301nh la\u0300 s\u00f4\u0301 t\u01b0\u0323 nhi\u00ean nho\u0309 nh\u00e2\u0301t.<\/p>\n\n\n\n

Nh\u01b0 chu\u0301ng ta bi\u00ea\u0301t s\u01b0\u0323 thay \u0111\u00f4\u0309i cu\u0309a th\u01a1\u0300i ti\u00ea\u0301t \u0111\u01b0\u01a1\u0323c bi\u00ea\u0309u hi\u00ea\u0323n b\u0103\u0300ng nhi\u00ea\u0323t \u0111\u00f4\u0323. 0 \u0111\u00f4\u0323 C co\u0301 pha\u0309i la\u0300 kh\u00f4ng co\u0301 gi\u0300? 0 \u0111\u00f4\u0323 C la\u0300 nhi\u00ea\u0323t \u0111\u00f4\u0323 cu\u0309a n\u01b0\u01a1\u0301c khi \u0111\u00f4\u0301ng b\u0103ng. Nhi\u00ea\u0323t \u0111\u00f4\u0323 l\u01a1\u0301n h\u01a1n 0 \u0111\u00f4\u0323 C la\u0300 nhi\u00ea\u0323t \u0111\u00f4\u0323 d\u01b0\u01a1ng, nho\u0309 h\u01a1n 0 la\u0300 nhi\u00ea\u0323t \u0111\u00f4\u0323 \u00e2m.<\/p>\n\n\n\n

Trong \u0111i\u00ea\u0323n a\u0301p, 0 la\u0300 m\u01b0\u0301c \u0111i\u00ea\u0323n a\u0301p th\u00e2\u0301p.<\/p>\n\n\n\n

Ba\u0309n th\u00e2n s\u00f4\u0301 0 ch\u01b0\u0301a r\u00e2\u0301t nhi\u00ea\u0300u s\u01b0\u0323 m\u00e2u thu\u00e2\u0303n. S\u00f4\u0301 na\u0300o c\u00f4\u0323ng v\u01a1\u0301i 0 cu\u0303ng b\u0103\u0300ng chi\u0301nh no\u0301. Trong khi ca\u0301c s\u00f4\u0301 nh\u00e2n v\u01a1\u0301i nhau chi\u0309 c\u00e2\u0300n xu\u00e2\u0301t hi\u00ea\u0323n m\u00f4\u0323t s\u00f4\u0301 0 la\u0300 k\u00ea\u0301t qua\u0309 b\u0103\u0300ng 0.<\/p>\n\n\n\n

S\u00f4\u0301 0 trong Toa\u0301n ho\u0323c th\u00e2\u0323t s\u01b0\u0323 r\u00e2\u0301t quan tro\u0323ng. Chuy\u00ea\u0309n t\u01b0\u0300 0 \u0111\u00ea\u0301n 1 la\u0300 qua\u0301 tri\u0300nh t\u01b0\u0300 kh\u00f4ng \u0111\u00ea\u0301n co\u0301. Trong khi t\u01b0\u0300 1 \u0111\u00ea\u0301n 100, 1000,\u2026 chi\u0309 la\u0300 s\u01b0\u0323 nhi\u00ea\u0300u l\u00ean.<\/p>\n\n\n\n

Nh\u01b0 v\u00e2\u0323y, ta co\u0301 th\u00ea\u0309 th\u00e2\u0301y ca\u0301c kha\u0301i ni\u00ea\u0323m trong Toa\u0301n ho\u0323c cu\u0323 th\u00ea\u0309 la\u0300 s\u00f4\u0301 ho\u0323c chi\u0309 mang ti\u0301nh t\u01b0\u01a1ng \u0111\u00f4\u0301i, kh\u00f4ng pha\u0309i la\u0300 b\u00e2\u0301t bi\u00ea\u0301n. S\u00f4\u0301 0 cu\u0303ng v\u00e2\u0323y.<\/p>\n\n\n\n

T\u00f4\u0309ng k\u00ea\u0301t<\/p>\n\n\n\n

Vietlearn hy vo\u0323ng v\u01a1\u0301i ba\u0300i vi\u00ea\u0301t tr\u00ean \u0111a\u0303 giu\u0301p ca\u0301c ba\u0323n ho\u0323c sinh ho\u0323c t\u00f4\u0301t ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c ti\u0301nh ch\u00e2\u0301t cu\u0309a da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau. \u0110\u00f4\u0300ng th\u01a1\u0300i, Vietlearn mong r\u0103\u0300ng ba\u0300i vi\u00ea\u0301t \u0111a\u0303 cung c\u00e2\u0301p cho ca\u0301c ba\u0323n th\u00eam nh\u01b0\u0303ng hi\u00ea\u0309u bi\u00ea\u0301t thu\u0301 vi\u0323 v\u00ea\u0300 m\u00f4n Toa\u0301n. Ca\u0301c ki\u00ea\u0301n th\u01b0\u0301c Toa\u0301n ho\u0323c r\u00e2\u0301t hay va\u0300 kh\u00f4ng h\u00ea\u0300 kho\u0301 nh\u01b0 suy nghi\u0303 cu\u0309a m\u00f4\u0323t s\u00f4\u0301 ba\u0323n ho\u0323c sinh. Cu\u0300ng y\u00eau Toa\u0301n ho\u0323c v\u01a1\u0301i Vietlearn ngay th\u00f4i na\u0300o. Ghe\u0301 qua blog Vietlearn \u0111\u00ea\u0309 tham kha\u0309o ca\u0301c bi\u0301 quy\u00ea\u0301t ho\u0323c t\u00e2\u0323p c\u01b0\u0323c ch\u00e2\u0301t cu\u0300ng ca\u0301c ki\u00ea\u0301n th\u01b0\u0301c va\u0300 ta\u0300i li\u00ea\u0323u ho\u0323c t\u00e2\u0323p mi\u00ea\u0303n phi\u0301 kh\u00f4\u0309ng l\u00f4\u0300.<\/p>\n\n\n\n

H\u1ecdc t\u1ed1t l\u1edbp 7<\/p>\n\n\n\n

Vietlearn \u2013 Gia s\u01b0<\/a> tr\u01b0\u0323c tuy\u00ea\u0301n s\u00f4\u0301 1 Vi\u00ea\u0323t Nam<\/p>\n\n\n\n

Vietlearn la\u0300 m\u00f4 hi\u0300nh gia\u0301o du\u0323c \u0111\u01b0\u01a1\u0323c t\u00f4\u0309 ch\u01b0\u0301 qu\u00f4\u0301c t\u00ea\u0301 \u0111a\u0301nh gia\u0301 cao, \u0111a\u0323t 93\/100 \u0111i\u00ea\u0309m theo ti\u00eau chu\u00e2\u0309n qu\u00f4\u0301c t\u00ea\u0301. Vietlearn la\u0300 gia\u0309i pha\u0301p hi\u00ea\u0323u qua\u0309 \u0111\u00ea\u0309 ca\u0309i thi\u00ea\u0323n ti\u0300nh hi\u0300nh ho\u0323c t\u00e2\u0323p cu\u0309a ca\u0301c ba\u0323n ho\u0323c sinh. V\u01a1\u0301i ca\u0301c ba\u0300i gia\u0309ng, kho\u0301a ho\u0323c tr\u01b0\u0323c tuy\u00ea\u0301n \u0111\u01b0\u01a1\u0323c thi\u00ea\u0301t k\u00ea\u0301 sinh \u0111\u00f4\u0323ng, tr\u01b0\u0323c quan, kh\u01a1i g\u01a1\u0323i h\u01b0\u0301ng thu\u0301 cho ng\u01b0\u01a1\u0300i ho\u0323c. Vietlearn s\u01b0\u0309 du\u0323ng c\u00f4ng ngh\u00ea\u0323 AI trong ph\u00e2n ti\u0301ch, ch\u00e2\u0301m ba\u0300i, \u0111a\u0301nh gia\u0301 \u0111i\u00ea\u0309m s\u00f4\u0301, \u01b0u \u0111i\u00ea\u0309m, ha\u0323n ch\u00ea\u0301 cu\u0309a ca\u0301c ba\u0323n ho\u0323c sinh. Tr\u00ean c\u01a1 s\u01a1\u0309 k\u00ea\u0301t qua\u0309 \u0111o\u0301, Vietlearn thi\u00ea\u0301t k\u00ea\u0301 l\u00f4\u0323 tri\u0300nh ho\u0323c t\u00e2\u0323p ri\u00eang bi\u00ea\u0323t, ca\u0301 nh\u00e2n ho\u0301a phu\u0300 h\u01a1\u0323p v\u01a1\u0301i t\u01b0\u0300ng ho\u0323c vi\u00ean. Vietlearn t\u01b0\u0323 tin co\u0301 th\u00ea\u0309 giu\u0301p ca\u0301c ba\u0323n ho\u0323c sinh ca\u0309i thi\u00ea\u0323n ti\u0300nh hi\u0300nh ho\u0323c t\u00e2\u0323p trong th\u01a1\u0300i gian ng\u0103\u0301n.<\/p>\n\n\n\n

Hi\u00ea\u0323n nay, kho\u0301a ho\u0323c K12 cu\u0309a Vietlearn \u0111ang thu hu\u0301t \u0111\u01b0\u01a1\u0323c r\u00e2\u0301t nhi\u00ea\u0300u ba\u0323n ho\u0323c sinh va\u0300 phu\u0323 huynh. K12 la\u0300 kho\u0301a ho\u0323c tr\u01b0\u0323c tuy\u00ea\u0301n da\u0300nh cho ho\u0323c sinh t\u01b0\u0300 l\u01a1\u0301p 1 \u0111\u00ea\u0301n l\u01a1\u0301p 12 v\u01a1\u0301i ca\u0301c m\u00f4n: Toa\u0301n, Ho\u0301a ho\u0323c, V\u00e2\u0323t Ly\u0301, Anh ng\u01b0\u0303. Ti\u0300m hi\u00ea\u0309u chi ti\u00ea\u0301t kho\u0301a ho\u0323c ta\u0323i \u0111\u00e2y<\/p>\n\n\n\n

<\/p>\n\n\n\n

Ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 T\u00e2\u0323p h\u01a1\u0323p Q ca\u0301c s\u00f4\u0301 h\u01b0\u0303u ti\u0309 \u2013 Gi\u1ecfi to\u00e1n l\u1edb<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":"

Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn Trong ba\u0300i vi\u00ea\u0301t tr\u01b0\u01a1\u0301c, Vietlearn \u0111a\u0303 cu\u0300ng ca\u0301c ba\u0323n ho\u0323c sinh ti\u0300m hi\u00ea\u0309u ca\u0301c ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 lu\u0303y th\u01b0\u0300a, ti\u0309 l\u00ea\u0323 th\u01b0\u0301c. Trong ba\u0300i vi\u00ea\u0301t na\u0300y, Vietlearn cu\u0300ng ca\u0301c ba\u0323n ti\u0300m hi\u00ea\u0309u ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c m\u01a1\u0301i. \u0110o\u0301 la\u0300 ti\u0301nh ch\u00e2\u0301t cu\u0309a da\u0303y ti\u0309 s\u00f4\u0301 b\u0103\u0300ng nhau. Ti\u0301nh ch\u00e2\u0301t da\u0303y […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[9,4],"tags":[],"class_list":["post-2653","post","type-post","status-publish","format-standard","hentry","category-toan-hoc","category-trung-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2653","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=2653"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2653\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=2653"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=2653"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=2653"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}