Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn<\/p>\n\n\n\n
\u01a0\u0309 ba\u0300i tr\u01b0\u01a1\u0301c, Vietlearn \u0111a\u0303 cu\u0300ng ca\u0301c ba\u0323n ho\u0323c sinh ti\u0300m hi\u00ea\u0309u ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309 la\u0300: kha\u0301i ni\u00ea\u0323m, phe\u0301p c\u00f4\u0323ng, tr\u01b0\u0300,\u2026 Trong ba\u0300i vi\u00ea\u0301t h\u00f4m nay, chu\u0301ng ta se\u0303 ti\u00ea\u0301p tu\u0323c ti\u0300m hi\u00ea\u0309u ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 phe\u0301p nh\u00e2n, chia s\u00f4\u0301 h\u01b0\u0303u ti\u0309. \u0110\u00e2y la\u0300 ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c c\u01a1 ba\u0309n mang ti\u0301nh n\u00ea\u0300n ta\u0309ng cu\u0309a ch\u01b0\u01a1ng tri\u0300nh Toa\u0301n 7. Ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c na\u0300y \u0111\u01b0\u01a1\u0323c m\u00f4\u0323t s\u00f4\u0301 ba\u0323n ho\u0323c sinh \u0111a\u0301nh gia\u0301 la\u0300 kha\u0301 ph\u01b0\u0301c ta\u0323p. Ha\u0303y cu\u0300ng Vietlearn ti\u0300m hi\u00ea\u0309u ngay sau \u0111\u00e2y:<\/p>\n\n\n\n
Phe\u0301p nh\u00e2n s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Nh\u00e2n hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Phe\u0301p nh\u00e2n s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Ta co\u0301: x = a\/b, y = c\/d (b va\u0300 d kha\u0301c 0)<\/p>\n\n\n\n
x . y = a\/b x c\/d = a x c \/ b x d<\/p>\n\n\n\n
Vi\u0301 du\u0323: x = 2\/8, y = 3\/7<\/p>\n\n\n\n
x . y = 2\/8 x 3\/7 = 2 x 3 \/ 8 x 7 = 6\/56<\/p>\n\n\n\n
L\u01b0u y\u0301:<\/p>\n\n\n\n
K\u00ea\u0301t qua\u0309 ca\u0301c phe\u0301p nh\u00e2n, phe\u0301p chia cu\u0309a nhi\u00ea\u0300u s\u00f4\u0301 h\u01b0\u0303u ti\u0309 mang d\u00e2\u0301u + khi s\u00f4\u0301 th\u01b0\u0300a s\u00f4\u0301 \u00e2m la\u0300 ch\u0103\u0303n.<\/p>\n\n\n\n
K\u00ea\u0301t qua\u0309 ca\u0301c phe\u0301p nh\u00e2n, phe\u0301p chia cu\u0309a nhi\u00ea\u0300u s\u00f4\u0301 h\u01b0\u0303u ti\u0309 mang d\u00e2\u0301u \u2013 khi s\u00f4\u0301 th\u01b0\u0300a s\u00f4\u0301 \u00e2m la\u0300 le\u0309.<\/p>\n\n\n\n
\u0110o\u0323c th\u00eam: Ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 T\u00e2\u0323p h\u01a1\u0323p Q ca\u0301c s\u00f4\u0301 h\u01b0\u0303u ti\u0309 \u2013 Gi\u1ecfi to\u00e1n l\u1edbp 7<\/p><\/blockquote>\n\n\n\n
Chia hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Phe\u0301p chia s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Ta co\u0301: x = a\/b, y = c\/d ( y, b, d kha\u0301c 0)<\/p>\n\n\n\n
x : y = a\/b : c\/d = a\/b x d\/c = a.d \/ b.c<\/p>\n\n\n\n
Vi\u0301 du\u0323: x = 4\/9, y = 5\/7<\/p>\n\n\n\n
x : y = 4\/9 : 5\/7 = 4\/9 x 7\/5 = 4 x 7 \/ 9 x 5 = 28\/45<\/p>\n\n\n\n
L\u01b0u y\u0301:<\/p>\n\n\n\n
V\u01a1\u0301i y la\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309 kha\u0301c 0, s\u00f4\u0301 nghi\u0323ch \u0111a\u0309o cu\u0309a y la\u0300 1\/y ( y x 1\/y = 1)<\/p>\n\n\n\n
K\u00ea\u0301t qua\u0309 th\u01b0\u01a1ng cu\u0309a phe\u0301p chia hai s\u00f4\u0301 h\u01b0\u0303u ti\u0309 x cho y trong \u0111o\u0301 y kha\u0301c 0 co\u0300n \u0111\u01b0\u01a1\u0323c go\u0323i la\u0300 ti\u0309 s\u00f4\u0301 gi\u01b0\u0303a x va\u0300 y. Ki\u0301 hi\u00ea\u0323u: x : y ho\u0103\u0323c x\/y.<\/p>\n\n\n\n
Ba\u0300i t\u00e2\u0323p v\u00e2\u0323n du\u0323ng<\/p>\n\n\n\n
Ba\u0300i t\u00e2\u0323p ti\u0301nh toa\u0301n c\u01a1 ba\u0309n<\/p>\n\n\n\n
Ba\u0300i 1: Ti\u0300m s\u00f4\u0301 h\u01b0\u0303u ti\u0309 x bi\u00ea\u0301t:<\/p>\n\n\n\n
a. 3x + 1\/7 = 0<\/p>\n\n\n\n
b. 2\/5x \u2013 3 = 6<\/p>\n\n\n\n
c. -1\/2 x ( x +3 ) = 7<\/p>\n\n\n\n
d. ( x + 3) . ( x + 1) > 0<\/p>\n\n\n\n
e. ( x \u2013 1) . ( x + 4) < 0<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i<\/p>\n\n\n\n
a.3x + 1\/7 = 0 => 3x = 0 \u2013 1\/7<\/p>\n\n\n\n
=> 3x = -1\/7<\/p>\n\n\n\n
=> x = -1\/7 : 3<\/p>\n\n\n\n
=> x = -1\/21<\/p>\n\n\n\n
b. 2\/5x \u2013 3 = 6<\/p>\n\n\n\n
=> 2\/5x = 6 + 3<\/p>\n\n\n\n
=> 2\/5x = 9<\/p>\n\n\n\n
=> x = 9 : \u2156<\/p>\n\n\n\n
=> x = 45\/2<\/p>\n\n\n\n
c. -\u00bd x ( x + 3) =7<\/p>\n\n\n\n
=> x + 3 = 7 : -\u00bd<\/p>\n\n\n\n
=> x + 3 = -14<\/p>\n\n\n\n
=> x = -17<\/p>\n\n\n\n
d. ( x + 3) . ( x + 1) > 0<\/p>\n\n\n\n
=> x + 3 > 0 va\u0300 x + 1 > 0<\/p>\n\n\n\n
=> x > -3 va\u0300 x > -1<\/p>\n\n\n\n
=> x > -1<\/p>\n\n\n\n
e. ( x \u2013 1) . ( x + 4) < 0<\/p>\n\n\n\n
TH1: x \u2013 1 < 0 va\u0300 x + 4 > 0<\/p>\n\n\n\n
=> x < 1 va\u0300 x > -4<\/p>\n\n\n\n
=> -4 < x < 1<\/p>\n\n\n\n
TH2: x -1 > 0 va\u0300 x + 4 < 0<\/p>\n\n\n\n
=> x > 1 va\u0300 x < -4<\/p>\n\n\n\n
=> Kh\u00f4ng co\u0301 x thoa\u0309 ma\u0303n 2 \u0111i\u00ea\u0300u ki\u00ea\u0323n tr\u00ean.<\/p>\n\n\n\n
Ba\u0300i 2: Th\u01b0\u0323c hi\u00ea\u0323n ca\u0301c phe\u0301p toa\u0301n sau:<\/p>\n\n\n\n
a. -8\/7 : 2\/3<\/p>\n\n\n\n
b. 4\/5 x 6\/9<\/p>\n\n\n\n
c. 1\/3 x ( 2\/5 : 3\/4 )<\/p>\n\n\n\n
d. 5\/10 : 8\/-9<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i<\/p>\n\n\n\n
-8\/7 : 2\/3 = -8\/7 x 3\/2 = -24\/14 = -12\/7<\/p>\n\n\n\n
4\/5 x 6\/9 = 4 . 6 \/ 5 . 9 = 20\/54 = 10\/27<\/p>\n\n\n\n
1\/3 x ( 2\/5 : 3\/4 ) = 1\/3 x ( 2\/5 x 4\/3) = 1\/3 x 8\/15 = 8\/45<\/p>\n\n\n\n
5\/10 : 8\/-9 = 5\/10 x -9\/8 = -45\/80 = -9\/16<\/p>\n\n\n\n
Ba\u0300i t\u00e2\u0323p n\u00e2ng cao<\/p>\n\n\n\n
Ba\u0300i 1: Cho A = 1\/ 1.2 + 1\/3 . 4 +\u2026+ 1\/99.100. Ch\u01b0\u0301ng minh 7\/12 < A < 5\/6<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i<\/p>\n\n\n\n
Ta co\u0301: 7\/12 = 1\/12 + 6\/12 = 1\/12 + 1\/2 = 1\/1.2 + 1\/3 .4 < A<\/p>\n\n\n\n
A = 1\/1.2 + 1\/3 .4 +\u2026+ 1\/99.100 = 1\/1.2 + (1\/3 x 4 + 1\/5 x 6 +\u2026+ 1\/99 x 100)<\/p>\n\n\n\n
A < 1\/2 + ( 1\/3 .4 + 1\/4 .5 + \u2026 + 1\/51. 52)<\/p>\n\n\n\n
Co\u0301:<\/p>\n\n\n\n
1\/2 + ( 1\/3 . 4 + 1\/4 .5 +\u2026+ 1\/51.52 )<\/p>\n\n\n\n
= 1\/2 + ( 1\/3 -1\/4 + 1\/4 \u2013 1\/5 + \u2026 + 1\/51 \u2013 1\/52)<\/p>\n\n\n\n
= 1\/2 + 1\/3 \u2013 1\/52 < 1\/2 + 1\/3<\/p>\n\n\n\n
V\u00e2\u0323y 7\/12 < A < \u215a<\/p>\n\n\n\n
Ba\u0300i 2: Ti\u0300m s\u00f4\u0301 h\u01b0\u0303u ti\u0309 x tho\u0309a ma\u0303n: -1\/15 \u2013 3\/8 x 6\/5 < x < 11\/15 : 0.9<\/p>\n\n\n\n
L\u01a1\u0300i gia\u0309i:<\/p>\n\n\n\n
-1\/15 \u2013 3\/8 x 6\/5 < x < 11\/15 : 0.9 => -1\/15 \u2013 9\/20 < x < 11\/15 x 10\/9 => -31\/60 < x < 22\/27<\/p>\n\n\n\n
Ta co\u0301: -1 = -60\/60 < -31\/60 < x < 22\/27 < 27\/27 = 1<\/p>\n\n\n\n
Ma\u0300 x la\u0300 s\u00f4\u0301 nguy\u00ean.<\/p>\n\n\n\n
V\u00e2\u0323y x = 0<\/p>\n\n\n\n
Bi\u0301 m\u00e2\u0323t Toa\u0301n ho\u0323c<\/p>\n\n\n\n
C\u00e2u chuy\u00ea\u0323n: \u201c\u0110\u00ea\u0309 1000 chi\u00ea\u0301c \u0111i\u0303a chi\u0309 trong 10 chi\u00ea\u0301c h\u00f4\u0323p\u201d<\/p>\n\n\n\n
Th\u00e2\u0323t kho\u0301 tin nh\u01b0ng th\u01b0\u0323c t\u00ea\u0301 co\u0301 m\u00f4\u0323t anh cha\u0300ng co\u0301 kha\u0309 n\u0103ng s\u0103\u0301p x\u00ea\u0301p r\u00e2\u0301t gio\u0309i. Ba\u0323n mu\u00f4\u0301n m\u01b0\u01a1\u0323n bao nhi\u00eau chi\u00ea\u0301c \u0111i\u0303a (trong khoa\u0309ng d\u01b0\u01a1\u0301i 1000 ca\u0301i) thi\u0300 anh \u00e2\u0301y cu\u0303ng chi\u0309 c\u00e2\u0300n \u0111\u01b0a cho ba\u0323n va\u0300i ca\u0301i h\u00f4\u0323p ma\u0300 kh\u00f4ng c\u00e2\u0300n m\u01a1\u0309 ra \u0111\u00ea\u0301m la\u0323i. S\u00f4\u0301 \u0111i\u0303a trong ca\u0301c h\u00f4\u0323p v\u01b0\u0300a khi\u0301t v\u01a1\u0301i s\u00f4\u0301 l\u01b0\u01a1\u0323ng ba\u0323n mong mu\u00f4\u0301n. Ba\u0323n co\u0301 to\u0300 mo\u0300 v\u00ea\u0300 ca\u0301ch s\u0103\u0301p x\u00ea\u0301p cu\u0309a anh cha\u0300ng th\u00f4ng minh na\u0300y kh\u00f4ng?<\/p>\n\n\n\n
Ly\u0301 gia\u0309i:<\/p>\n\n\n\n
Ca\u0301ch 1:<\/p>\n\n\n\n
Anh cha\u0300ng th\u00f4ng mi\u0300nh \u0111a\u0303 s\u01b0\u0309 du\u0323ng 10 chi\u00ea\u0301c h\u00f4\u0323p. \u0110a\u0301nh s\u00f4\u0301 th\u01b0\u0301 t\u01b0\u0323 l\u00e2\u0300n l\u01b0\u01a1\u0323t t\u01b0\u0300 1 \u0111\u00ea\u0301n 10. Trong 10 chi\u00ea\u0301c h\u00f4\u0323p na\u0300y, anh l\u00e2\u0300n l\u01b0\u01a1\u0323t bo\u0309 va\u0300o: 1, 2, 4, 8, 16, 32, 64, 128, 256, 489 chi\u00ea\u0301c \u0111i\u0303a. Nh\u01b0 v\u00e2\u0323y, 1000 chi\u00ea\u0301c \u0111i\u0303a \u0111a\u0303 \u0111\u01b0\u01a1\u0323c bo\u0309 va\u0300o 10 chi\u00ea\u0301c h\u00f4\u0323p. (1 + 2 + 4 + 8 + 16 + 32 + 64 +128 +256 + 489 = 1000).<\/p>\n\n\n\n
N\u1ebfu b\u1ea1n mu\u1ed1n m\u01b0\u1ee3n 1 chi\u1ebfc, anh ta ch\u1ec9 c\u1ea7n l\u1ea5y h\u1ed9p s\u1ed1 1 l\u00e0 \u0111\u01b0\u1ee3c.<\/p>\n\n\n\n
N\u1ebfu b\u1ea1n mu\u1ed1n m\u01b0\u1ee3n s\u1ed1 l\u01b0\u1ee3ng \u0111\u0129a \u00edt h\u01a1n 4 chi\u1ebfc. Anh ta s\u1ebd ch\u1ecdn l\u1ea5y gi\u1eefa h\u1ed9p s\u1ed1 1 v\u00e0 h\u1ed9p s\u1ed1 2. V\u00ed d\u1ee5 b\u1ea1n m\u01b0\u1ee3n 2 chi\u1ebfc. Anh ta l\u1ea5y cho b\u1ea1n h\u1ed9p s\u1ed1 2. Ba\u0323n m\u01b0\u1ee3n 3 chi\u1ebfc, anh ta l\u1ea5y ra h\u1ed9p s\u1ed1 1 v\u00e0 s\u1ed1 2.<\/p>\n\n\n\n
N\u1ebfu b\u1ea1n m\u01b0\u1ee3n s\u1ed1 l\u01b0\u1ee3ng \u00edt h\u01a1n 8 chi\u1ebfc. Anh ta ch\u1ec9 c\u1ea7n t\u00ednh to\u00e1n gi\u1eefa h\u1ed9p s\u1ed1 1 \u0111\u1ebfn h\u1ed9p s\u1ed1 3. Anh ta se\u0303 l\u1ea5y ra \u0111\u01b0\u1ee3c \u0111\u00fang s\u1ed1 \u0111\u0129a b\u1ea1n c\u1ea7n m\u01b0\u1ee3n. V\u00ed d\u1ee5 b\u1ea1n m\u01b0\u1ee3n 6 chi\u1ebfc \u0111\u0129a. Anh \u00e2\u0301y se\u0303 l\u1ea5y cho b\u1ea1n h\u1ed9p s\u1ed1 2 v\u00e0 3. V\u00ec 2 + 4 = 6<\/p>\n\n\n\n
B\u1ea1n m\u01b0\u1ee3n 7 chi\u1ebfc \u0111\u0129a. Anh ta se\u0303 l\u1ea5y h\u1ed9p s\u1ed1 1, s\u1ed1 2, s\u1ed1 3. V\u00ec 1 + 2 + 4 = 7.<\/p>\n\n\n\n
C\u1ee9 suy l\u1ea7n l\u01b0\u1ee3t nh\u01b0 v\u1eady, n\u1ebfu b\u1ea1n c\u1ea7n s\u1ed1 l\u01b0\u1ee3ng \u0111\u0129a \u00edt h\u01a1n con s\u1ed1 512 chi\u1ebfc. Anh ta ch\u1ec9 c\u1ea7n t\u00ednh to\u00e1n gi\u1eefa c\u00e1c h\u1ed9p s\u1ed1 1 \u0111\u1ebfn s\u1ed1 9 l\u00e0 \u0111\u01b0\u1ee3c, kh\u00f4ng tin b\u1ea1n c\u1ee9 th\u1eed t\u00ednh m\u00e0 xem.<\/p>\n\n\n\n
N\u00ea\u0301u ba\u0323n tinh y\u0301 se\u0303 nh\u00e2\u0323n ra s\u00f4\u0301 \u0111i\u0303a \u01a1\u0309 thu\u0300ng th\u01b0\u0301 10 kh\u00f4ng theo quy lu\u00e2\u0323t cu\u0309a ca\u0301c thu\u0300ng tr\u01b0\u01a1\u0301c. Anh na\u0300y x\u00ea\u0301p s\u00f4\u0301 \u0111i\u0301a \u01a1\u0309 thu\u0300ng th\u01b0\u0301 1 g\u00e2\u0301p 2 s\u00f4\u0301 \u0111i\u0303a thu\u0300ng th\u01b0\u0301 2 va\u0300 c\u01b0\u0301 t\u01b0\u01a1ng t\u01b0\u0323 nh\u01b0 v\u00e2\u0323y cho \u0111\u00ea\u0301n h\u00ea\u0301t. Theo \u0111u\u0301ng quy lu\u00e2\u0323t na\u0300y thi\u0300 thu\u0301ng th\u01b0\u0301 10 pha\u0309i \u0111\u01b0\u0323ng 512 chi\u00ea\u0301c \u0111i\u0303a. V\u00e2\u0323y ta\u0323i sao thu\u0300ng 10 cu\u0309a anh ta chi\u0309 co\u0301 489 chi\u00ea\u0301c? Ly\u0301 gia\u0309i cho \u0111i\u00ea\u0300u na\u0300y \u0111o\u0301 la\u0300 do chi\u0309 co\u0301 1000 chi\u00ea\u0301c \u0111i\u0303a n\u00ean n\u00ea\u0301u x\u00ea\u0301p thu\u0300ng th\u01b0\u0301 10 la\u0300 512 \u0111i\u0303a thi\u0300 t\u00f4\u0309ng s\u00f4\u0301 \u0111i\u0303a se\u0303 thay \u0111\u00f4\u0309i tha\u0300nh 1032 chi\u00ea\u0301c.<\/p>\n\n\n\n
Ca\u0301ch 2:<\/p>\n\n\n\n
M\u00f4\u0323t \u0111a\u0301p a\u0301n chi\u0301nh xa\u0301c kha\u0301c cu\u0309a ba\u0300i toa\u0301n na\u0300y \u0111o\u0301 la\u0300 anh co\u0301 th\u00ea\u0309 s\u0103\u0301p thu\u0300ng th\u01b0\u0301 9 la\u0300 245 \u0111i\u0303a va\u0300 thu\u0300ng 10 la\u0300 500 chi\u00ea\u0301c \u0111i\u0303a. Nh\u01b0\u0303ng h\u00f4\u0323p co\u0300n la\u0323i s\u00f4\u0301 l\u01b0\u01a1\u0323ng \u0111i\u0303a kh\u00f4ng thay \u0111\u00f4\u0309i. Ba\u0300i Toa\u0301n na\u0300y th\u00e2\u0323t thu\u0301 vi\u0323 pha\u0309i kh\u00f4ng na\u0300o?<\/p>\n\n\n\n
Bi\u0301 quy\u00ea\u0301t \u0111\u00ea\u0309 n\u0103\u0301m v\u01b0\u0303ng ki\u00ea\u0301n th\u01b0\u0301c s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
S\u00f4\u0301 h\u01b0\u0303u ti\u0309 la\u0300 ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c c\u01a1 ba\u0309n va\u0300 quan tro\u0323ng trong ch\u01b0\u01a1ng tri\u0300nh Toa\u0301n 7. Vi\u00ea\u0323c m\u01a1\u0301i la\u0300m quen v\u01a1\u0301i ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c na\u0300y khi\u00ea\u0301n nhi\u00ea\u0300u ba\u0323n ho\u0323c sinh ca\u0309m th\u00e2\u0301y b\u00f4\u0301i r\u00f4\u0301i, kho\u0301 kh\u0103n. La\u0300m th\u00ea\u0301 na\u0300o \u0111\u00ea\u0309 ho\u0323c t\u00f4\u0301t ca\u0301c ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309? Vietlearn ma\u0301ch cho ba\u0323n m\u00f4\u0323t va\u0300i bi\u0301 quy\u00ea\u0301t nho\u0309:<\/p>\n\n\n\n
N\u0103\u0301m v\u01b0\u0303ng \u0111i\u0323nh nghi\u0303a, ly\u0301 thuy\u00ea\u0301t, ki\u00ea\u0301n th\u01b0\u0301c c\u01a1 ba\u0309n. \u0110\u00ea\u0309 n\u0103\u0301m v\u01b0\u0303ng ki\u00ea\u0301n th\u01b0\u0301c, chu\u0301ng ta c\u00e2\u0300n pha\u0309i chu\u0301 y\u0301 nghe gia\u0309ng tr\u00ean l\u01a1\u0301p. Sau \u0111o\u0301, khi v\u00ea\u0300 nha\u0300 chu\u0301ng ta c\u00e2\u0300n ti\u0301ch c\u01b0\u0323c \u00f4n t\u00e2\u0323p, ng\u00e2\u0303m la\u0323i \u0111\u00ea\u0309 hi\u00ea\u0309u s\u00e2u ki\u00ea\u0301n th\u01b0\u0301c. V\u01a1\u0301i nh\u01b0\u0303ng th\u0103\u0301c m\u0103\u0301c, chu\u0301ng ta c\u00e2\u0300n gia\u0309i quy\u00ea\u0301t ca\u0300ng s\u01a1\u0301m ca\u0300ng t\u00f4\u0301t. Co\u0301 r\u00e2\u0301t nhi\u00ea\u0300u ca\u0301ch nh\u01b0: ho\u0309i tr\u01b0\u0323c ti\u00ea\u0301p th\u00e2\u0300y c\u00f4, ho\u0309i ba\u0323n be\u0300, ho\u0103\u0323c l\u00ean xem ca\u0301c ba\u0300i gia\u0309ng tr\u01b0\u0323c tuy\u00ea\u0301n.<\/p>\n\n\n\n
Re\u0300n luy\u00ea\u0323n d\u01b0\u01a1\u0301i nhi\u00ea\u0300u da\u0323ng ba\u0300i t\u00e2\u0323p la\u0300 ca\u0301ch t\u00f4\u0301t nh\u00e2\u0301t \u0111\u00ea\u0309 ho\u0323c t\u00f4\u0301t. Chu\u0301ng ta chi\u0309 th\u01b0\u0323c s\u01b0\u0323 hi\u00ea\u0309u ly\u0301 thuy\u00ea\u0301t khi bi\u00ea\u0301t s\u01b0\u0309 du\u0323ng no\u0301. V\u01a1\u0301i ca\u0301c ba\u0300i t\u00e2\u0323p \u0111\u00e2\u0300u ti\u00ean chu\u0301ng ta se\u0303 ca\u0309m th\u00e2\u0301y kha\u0301 kho\u0301 kh\u0103n. Nh\u01b0ng ba\u0323n \u0111\u01b0\u0300ng chu\u0300n b\u01b0\u01a1\u0301c ha\u0303y ki\u00ean tri\u0300 luy\u00ea\u0323n t\u00e2\u0323p. Sau 2 \u0111\u00ea\u0301n 3 ba\u0300i, t\u01b0 duy toa\u0301n ho\u0323c se\u0303 \u0111\u01b0\u01a1\u0323c ca\u0309i thi\u00ea\u0323n r\u00e2\u0301t nhi\u00ea\u0300u.<\/p>\n\n\n\n
H\u1ecdc t\u1ed1t l\u1edbp 7<\/p>\n\n\n\n
L\u01a1\u0300i k\u00ea\u0301t<\/p>\n\n\n\n
Tr\u00ean la\u0300 ly\u0301 thuy\u00ea\u0301t va\u0300 ca\u0301c da\u0323ng ba\u0300i t\u00e2\u0323p c\u01a1 ba\u0309n v\u00ea\u0300 phe\u0301p nh\u00e2n, chia s\u00f4\u0301 h\u01b0\u0303u ti\u0309. Vietlearn hy vo\u0323ng s\u00f4\u0301 h\u01b0\u0303u ti\u0309 se\u0303 kh\u00f4ng co\u0300n la\u0300 ph\u00e2\u0300n ki\u00ea\u0301n th\u01b0\u0301c g\u00e2y kho\u0301 kh\u0103n cho ca\u0301c ba\u0323n ho\u0323c sinh. \u01a0\u0309 m\u00f4\u0303i ba\u0300i vi\u00ea\u0301t, Vietlearn se\u0303 co\u0301 nh\u01b0\u0303ng b\u00e2\u0323t mi\u0301 Toa\u0301n ho\u0323c thu\u0301 vi\u0323 da\u0300nh cho ba\u0323n \u0111o\u0323c. Ghe\u0301 ngay blog Vietlearn \u0111\u00ea\u0309 ti\u0300m hi\u00ea\u0309u th\u00eam ca\u0301c ki\u00ea\u0301n th\u01b0\u0301c va\u0300 bi\u0301 m\u00e2\u0323t Toa\u0301n ho\u0323c ngay nhe\u0301.<\/p>\n\n\n\n
Truy c\u00e2\u0323p ngay blog Vietlearn tham kha\u0309o kho ho\u0323c li\u00ea\u0323u mi\u00ea\u0303n phi\u0301 c\u01b0\u0323c ch\u00e2\u0301t. Tham kha\u0309o kho\u0301a ho\u0323c K12 cu\u0309a Vietlearn ca\u0301c m\u00f4n ho\u0323c: Toa\u0301n, Ly\u0301, Anh,\u2026 da\u0300nh cho ho\u0323c sinh t\u01b0\u0300 l\u01a1\u0301p 1 \u0111\u00ea\u0301n l\u01a1\u0301p 12. Vietlearn t\u01b0\u0323 tin co\u0301 th\u00ea\u0309 giu\u0301p ca\u0301c ba\u0323n ho\u0323c sinh ca\u0309i thi\u00ea\u0323n \u0111i\u00ea\u0309m s\u00f4\u0301 trong th\u01a1\u0300i gian ng\u0103\u0301n, t\u01b0\u0323 tin trong ho\u0323c t\u00e2\u0323p.<\/p>\n\n\n\n
<\/p>\n\n\n\n
Ho\u0323c Toa\u0301n 7 cu\u0300ng Vietlearn: Ly\u0301 thuy\u00ea\u0301t & Ba\u0300i t\u00e2\u0323p c\u00f4\u0323ng tr\u01b0\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309<\/p>\n\n\n\n
Ho\u0323c T<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":"
Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn \u01a0\u0309 ba\u0300i tr\u01b0\u01a1\u0301c, Vietlearn \u0111a\u0303 cu\u0300ng ca\u0301c ba\u0323n ho\u0323c sinh ti\u0300m hi\u00ea\u0309u ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 s\u00f4\u0301 h\u01b0\u0303u ti\u0309 la\u0300: kha\u0301i ni\u00ea\u0323m, phe\u0301p c\u00f4\u0323ng, tr\u01b0\u0300,\u2026 Trong ba\u0300i vi\u00ea\u0301t h\u00f4m nay, chu\u0301ng ta se\u0303 ti\u00ea\u0301p tu\u0323c ti\u0300m hi\u00ea\u0309u ki\u00ea\u0301n th\u01b0\u0301c v\u00ea\u0300 phe\u0301p nh\u00e2n, chia s\u00f4\u0301 h\u01b0\u0303u ti\u0309. \u0110\u00e2y la\u0300 ph\u00e2\u0300n ki\u00ea\u0301n […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[9,4],"tags":[],"class_list":["post-2671","post","type-post","status-publish","format-standard","hentry","category-toan-hoc","category-trung-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2671","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=2671"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2671\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=2671"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=2671"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=2671"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}