Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn<\/p>\n\n\n\n
Quy t\u1eafc chuy\u1ec3n v\u1ebf trong ch\u01b0\u01a1ng tr\u00ecnh to\u00e1n<\/a> l\u1edbp 6 l\u00e0 m\u1ed9t trong nh\u1eefng b\u00e0i h\u1ecdc c\u01a1 b\u1ea3n. H\u1ecdc sinh<\/a> c\u1ea7n n\u1eafm v\u1eefng d\u1ea1ng to\u00e1n n\u00e0y. \u0110\u1ec3 c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng v\u00e0 m\u1edf r\u1ed9ng ki\u1ebfn th\u1ee9c trong nh\u1eefng b\u00e0i h\u1ecdc sau. H\u00e3y \u0111\u1ec3 toppy \u0111\u1ed3ng h\u00e0nh c\u00f9ng con chinh ph\u1ee5c m\u00f4n to\u00e1n h\u1ecdc l\u1edbp 6. V\u1edbi nh\u1eefng l\u00fd thuy\u1ebft c\u0103n b\u1ea3n v\u00e0 h\u01b0\u1edbng d\u1eabn gi\u1ea3i b\u00e0i t\u1eadp quy t\u1eafc chuy\u1ec3n v\u1ebf.<\/p>\n\n\n\n T\u00f3m t\u1eaft ki\u1ebfn th\u1ee9c l\u00fd thuy\u1ebft Quy t\u1eafc chuy\u1ec3n v\u1ebf \u2013 To\u00e1n h\u1ecdc l\u1edbp 6<\/p>\n\n\n\n T\u00ednh ch\u1ea5t c\u1ee7a \u0111\u1eb3ng th\u1ee9c<\/p>\n\n\n\n Theo t\u00ednh ch\u1ea5t c\u1ee7a \u0111\u1eb3ng th\u1ee9c. V\u1edbi m\u1ecdi s\u1ed1 a, b, c thu\u1ed9c t\u1eadp h\u1ee3p s\u1ed1 nguy\u00ean. Ta c\u00f3:<\/p>\n\n\n\n N\u1ebfu ta c\u00f3 bi\u1ec3u th\u1ee9c a = b th\u00ec a + c = b + c<\/p>\n\n\n\n Ng\u01b0\u1ee3c l\u1ea1i, n\u1ebfu ta c\u00f3 \u0111\u1eb3ng th\u1ee9c a + c = b + c th\u00ec a = b<\/p>\n\n\n\n V\u00e0 n\u1ebfu a = b th\u00ec b = a.<\/p>\n\n\n\n T\u00ednh ch\u1ea5t c\u1ee7a \u0111\u1eb3ng th\u1ee9c<\/p>\n\n\n\n \u0110\u1ec3 hi\u1ec3u r\u00f5 h\u01a1n v\u1ec1 t\u00ednh ch\u1ea5t n\u00e0y, toppy s\u1ebd c\u00f9ng c\u00e1c em ph\u00e2n t\u00edch v\u00ed d\u1ee5 sau \u0111\u00e2y:<\/p>\n\n\n\n V\u00ed d\u1ee5: N\u1ebfu ta c\u00f3 \u0111\u1eb3ng th\u1ee9c 12 + 8 + 6 \u2013 x = y + 12- 8 \u2013 3<\/p>\n\n\n\n Ta s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c nh\u1eefng \u0111\u1eb3ng th\u1ee9c \u0111\u00fang nh\u01b0 sau:<\/p>\n\n\n\n (12 + 8 + 6 \u2013 x) + 12 = (y +12 \u2013 8 \u2013 3) + 12<\/p>\n\n\n\n 12 + 8 + 6 \u2013 x = y + 12 \u2013 8 \u2013 3<\/p>\n\n\n\n y + 12 \u2013 8 \u2013 3 = 12 + 8 + 6 \u2013 x<\/p>\n\n\n\n Quy t\u1eafc chuy\u1ec3n v\u1ebf to\u00e1n l\u1edbp 6<\/p>\n\n\n\n Theo quy t\u1eafc chuy\u1ec3n v\u1ebf, ta c\u00f3 th\u1ec3 ph\u00e1t bi\u1ec3u nh\u01b0 sau: Khi chuy\u1ec3n m\u1ed9t s\u1ed1 h\u1ea1ng trong m\u1ed9t \u0111\u1eb3ng th\u1ee9c t\u1eeb v\u1ebf n\u00e0y sang v\u1ebf kia. Ta ph\u1ea3i \u0111\u1ed5i d\u1ea5u s\u1ed1 h\u1ea1ng \u0111\u00f3. N\u1ebfu s\u1ed1 h\u1ea1ng l\u00e0 s\u1ed1 nguy\u00ean d\u01b0\u01a1ng, ta \u0111\u1ed5i d\u1ea5u c\u1ed9ng th\u00e0nh d\u1ea5u tr\u1eeb. V\u00e0 ng\u01b0\u1ee3c l\u1ea1i, n\u1ebfu s\u1ed1 h\u1ea1ng l\u00e0 s\u1ed1 nguy\u00ean \u00e2m, ta \u0111\u1ed5i d\u1ea5u tr\u1eeb th\u00e0nh d\u1ea5u c\u1ed9ng.<\/p>\n\n\n\n T\u00f3m t\u1eaft l\u1ea1i, ta c\u00f3 c\u00f4ng th\u1ee9c:<\/p>\n\n\n\n x = a \u2013 b, sau khi chuy\u1ec3n v\u1ebf ta c\u00f3: x + b = a<\/p>\n\n\n\n V\u00e0 chuy\u1ec3n ng\u01b0\u1ee3c l\u1ea1i, khi x + b = a, chuy\u1ec3n v\u1ebf b ta \u0111\u01b0\u1ee3c: x = a \u2013 b<\/p>\n\n\n\n Nh\u01b0 v\u1eady, n\u1ebfu x l\u00e0 hi\u1ec7u c\u1ee7a 2 s\u1ed1 a v\u00e0 b, th\u00ec a s\u1ebd l\u00e0 t\u1ed5ng c\u1ee7a 2 s\u1ed1 x v\u00e0 b. Hay n\u00f3i theo m\u1ed9t c\u00e1ch kh\u00e1c, th\u00f4ng qua quy t\u1eafc chuy\u1ec3n v\u1ebf. Ph\u00e9p tr\u1eeb \u0111\u01b0\u1ee3c xem nh\u01b0 l\u00e0 ph\u00e9p t\u00ednh ng\u01b0\u1ee3c l\u1ea1i c\u1ee7a t\u00ednh c\u1ed9ng.<\/p>\n\n\n\n Quy t\u1eafc chuy\u1ec3n v\u1ebf to\u00e1n l\u1edbp 6<\/p>\n\n\n\n V\u00ed d\u1ee5:<\/p>\n\n\n\n 12 \u2013 8 \u2013 9 + 46 + 25 + x = y \u2013 2y + 16 \u2013 53<\/p>\n\n\n\n Chuy\u1ec3n v\u1ebf c\u00e1c h\u1ea1ng t\u1eed x, y, 2y ta \u0111\u01b0\u1ee3c:<\/p>\n\n\n\n 12 \u2013 8 \u2013 9 + 46 + 25 \u2013 y + 2y = 16 \u2013 53 \u2013 x<\/p>\n\n\n\n K\u1ebft lu\u1eadn: C\u00e1c em h\u1ecdc sinh<\/a> khi l\u00e0m b\u00e0i t\u1eadp d\u1ea1ng n\u00e0y c\u00f3 th\u1ec3 nh\u1edb quy t\u1eafc chuy\u1ec3n v\u1ebf. Th\u00f4ng qua kh\u1ea9u ng\u1eef: Chuy\u1ec3n v\u1ebf \u2013 \u0111\u1ed5i gi\u1ea5u. \u0110\u1ec3 tr\u00e1nh nh\u1ea7m l\u1eabn hay qu\u00ean quy t\u1eafc trong qu\u00e1 tr\u00ecnh l\u00e0m b\u00e0i.<\/p>\n\n\n\n M\u1ed9t s\u1ed1 d\u1ea1ng to\u00e1n quy t\u1eafc chuy\u1ec3n v\u1ebf<\/p>\n\n\n\n D\u1ea1ng to\u00e1n 1: T\u00ecm x trong \u0111\u1eb3ng th\u1ee9c hay c\u00f2n g\u1ecdi l\u00e0 t\u00ecm m\u1ed9t s\u1ed1 h\u1ea1ng ch\u01b0a bi\u1ebft trong \u0111\u1eb3ng th\u1ee9c<\/p>\n\n\n\n Ph\u01b0\u01a1ng ph\u00e1p l\u00e0m b\u00e0i: \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p t\u01b0\u01a1ng t\u1ef1 c\u00e1c d\u1ea1ng to\u00e1n t\u00ecm x th\u00f4ng th\u01b0\u1eddng. Tuy nhi\u00ean, c\u00f3 k\u1ebft h\u1ee3p t\u00ednh ch\u1ea5t c\u1ee7a \u0111\u1eb3ng th\u1ee9c, ph\u01b0\u01a1ng ph\u00e1p b\u1ecf d\u1ea5u ngo\u1eb7c. V\u00e0 quy t\u1eafc chuy\u1ec3n v\u1ebf \u0111\u1ec3 \u0111\u01b0a b\u00e0i l\u00e0m v\u1ec1 d\u1ea1ng \u0111\u01a1n gi\u1ea3n h\u01a1n.<\/p>\n\n\n\n V\u00ed d\u1ee5 1: T\u00ecm s\u1ed1 nguy\u00ean x, bi\u1ebft:<\/p>\n\n\n\n a) 5 \u2013 x = 9 \u2013 (- 5); b) x \u2013 6 = (- 2) \u2013 6<\/p>\n\n\n\n D\u1ea1ng to\u00e1n 1: T\u00ecm x trong \u0111\u1eb3ng th\u1ee9c hay c\u00f2n g\u1ecdi l\u00e0 t\u00ecm m\u1ed9t s\u1ed1 h\u1ea1ng ch\u01b0a bi\u1ebft trong \u0111\u1eb3ng th\u1ee9c<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i<\/p>\n\n\n\n a) 5 \u2013 x = 9 \u2013 (- 5)<\/p>\n\n\n\n 5 \u2013 x = 9 + 5<\/p>\n\n\n\n \u2013 x = 9 (\u00e1p d\u1ee5ng t\u00ednh ch\u1ea5t c\u1ee7a \u0111\u1eb3ng th\u1ee9c)<\/p>\n\n\n\n x = \u2013 9.<\/p>\n\n\n\n b) x \u2013 6 = (- 2) \u2013 6<\/p>\n\n\n\n x = \u2013 2 (\u00e1p d\u1ee5ng t\u00ednh ch\u1ea5t c\u1ee7a \u0111\u1eb3ng th\u1ee9c)<\/p>\n\n\n\n V\u00ed d\u1ee5 2: T\u00ecm s\u1ed1 nguy\u00ean x, bi\u1ebft r\u1eb1ng t\u1ed5ng c\u1ee7a 3 s\u1ed1 : 5 , \u2013 8 v\u00e0 x b\u1eb1ng 24.<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i<\/p>\n\n\n\n Theo \u0111\u1ec1 b\u00e0i, ta c\u00f3 :<\/p>\n\n\n\n 5 + (- 8) + x = 24<\/p>\n\n\n\n \u2013 8 + x = 19<\/p>\n\n\n\n x = 19+ 8<\/p>\n\n\n\n x = 27<\/p>\n\n\n\n \u00c1p d\u1ee5ng t\u01b0\u01a1ng t\u1ef1, m\u1eddi c\u00e1c em h\u1ecdc sinh<\/a> gi\u1ea3i c\u00e1c b\u00e0i t\u1eadp v\u00ed d\u1ee5 d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n\n\n\n V\u00ed d\u1ee5 3: Cho a \u2208 Z. T\u00ecm s\u1ed1 nguy\u00ean x, bi\u1ebft :<\/p>\n\n\n\n a) a + x = 10; b)a-x = 20.<\/p>\n\n\n\n \u0110\u00e1p s\u1ed1<\/p>\n\n\n\n a) x = 10 \u2013 a ; b) x = a \u2013 20.<\/p>\n\n\n\n V\u00ed d\u1ee5 4: Cho a, b \u2208 Z. T\u00ecm s\u1ed1 nguy\u00ean x, bi\u1ebft :<\/p>\n\n\n\n a)a + x = b; b) a \u2013 x = b.<\/p>\n\n\n\n \u0110\u00e1p s\u1ed1<\/p>\n\n\n\n a) x = b \u2013 a; b) x = a \u2013 b.<\/p>\n\n\n\n D\u1ea1ng to\u00e1n 2: T\u00ednh c\u00e1c t\u1ed5ng \u0111\u1ea1i s\u1ed1<\/p>\n\n\n\n Ph\u01b0\u01a1ng ph\u00e1p l\u00e0m b\u00e0i: Thay \u0111\u1ed5i v\u1ecb tr\u00ed c\u00e1c s\u1ed1 h\u1ea1ng trong \u0111\u1eb3ng th\u1ee9c. Sau \u0111\u00f3 \u00e1p d\u1ee5ng linh ho\u1ea1t c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a \u0111\u1eb3ng th\u1ee9c, quy t\u1eafc \u0111\u1ed5i d\u1ea5u,\u2026 \u0110\u1ec3 l\u00e0m b\u00e0i to\u00e1n tr\u1edf n\u00ean \u0111\u01a1n gi\u1ea3n h\u01a1n. V\u00e0 t\u00ednh t\u1ed5ng \u0111\u1ea1i s\u1ed1 d\u1ea1ng c\u01a1 b\u1ea3n.<\/p>\n\n\n\n D\u1ea1ng to\u00e1n 2: T\u00ednh c\u00e1c t\u1ed5ng \u0111\u1ea1i s\u1ed1<\/p>\n\n\n\n V\u00ed d\u1ee5 1: T\u00ednh :<\/p>\n\n\n\n a) (- 168) + (-422) ; b) -46 + 50 ; c) 31 \u2013 53 ;<\/p>\n\n\n\n d) 18 \u2013 26 -12 ; e) (- 28) + 32 \u2013 19.<\/p>\n\n\n\n \u0110\u00e1p s\u1ed1<\/p>\n\n\n\n a) \u2013 590 ; b) 4 ; c) -22 ; d) \u2013 20 ; e) \u2013 15.<\/p>\n\n\n\n V\u00ed d\u1ee5 8: T\u00ednh c\u00e1c t\u1ed5ng sau m\u1ed9t c\u00e1ch h\u1ee3p l\u00ed :<\/p>\n\n\n\n a) 3784 + 23 \u2013 3785 \u2013 15 ;<\/p>\n\n\n\n b) 21 + 22 + 23 + 24 \u2013 11 \u2013 12 \u2013 13 \u2013 14.<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i b\u00e0i t\u1eadp Quy t\u1eafc chuy\u1ec3n v\u1ebf s\u00e1ch gi\u00e1o khoa to\u00e1n l\u1edbp 6<\/p>\n\n\n\n B\u00e0i 61 (trang 87 SGK To\u00e1n 6 T\u1eadp 1):<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i b\u00e0i t\u1eadp Quy t\u1eafc chuy\u1ec3n v\u1ebf s\u00e1ch gi\u00e1o khoa to\u00e1n l\u1edbp 6<\/p>\n\n\n\n B\u00e0i 62 (trang 87 SGK To\u00e1n 6 T\u1eadp 1):<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i b\u00e0i t\u1eadp Quy t\u1eafc chuy\u1ec3n v\u1ebf s\u00e1ch gi\u00e1o khoa to\u00e1n l\u1edbp 6<\/p>\n\n\n\n B\u00e0i 63 (trang 87 SGK To\u00e1n 6 T\u1eadp 1):<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i b\u00e0i t\u1eadp Quy t\u1eafc chuy\u1ec3n v\u1ebf s\u00e1ch gi\u00e1o khoa to\u00e1n l\u1edbp 6<\/p>\n\n\n\n B\u00e0i 64 (trang 87 SGK To\u00e1n 6 T\u1eadp 1):<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i b\u00e0i t\u1eadp Quy t\u1eafc chuy\u1ec3n v\u1ebf s\u00e1ch gi\u00e1o khoa to\u00e1n l\u1edbp 6<\/p>\n\n\n\n B\u00e0i 65 (trang 87 SGK To\u00e1n 6 T\u1eadp 1):<\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i b\u00e0i t\u1eadp Quy t\u1eafc chuy\u1ec3n v\u1ebf s\u00e1ch gi\u00e1o khoa to\u00e1n l\u1edbp 6<\/p>\n\n\n\n B\u00ed quy\u1ebft chinh ph\u1ee5c m\u00f4n to\u00e1n l\u1edbp 6<\/p>\n\n\n\n \u0110\u1ec3 h\u1ecdc t\u1ed1t to\u00e1n l\u1edbp 6, \u0111\u1ea7u ti\u00ean, tr\u1ebb c\u1ea7n \u0111\u01b0\u1ee3c r\u00e8n luy\u1ec7n nh\u1eefng k\u1ef9 n\u0103ng<\/a> m\u1ec1m quan tr\u1ecdng.<\/p>\n\n\n\n Nh\u01b0 k\u1ef9 n\u0103ng<\/a> t\u00ednh to\u00e1n, k\u1ef9 n\u0103ng<\/a> tr\u00ecnh b\u00e0y hay k\u1ef9 n\u0103ng t\u01b0 duy h\u00ecnh h\u1ecdc. B\u01b0\u1edbc qua giai \u0111o\u1ea1n trung h\u1ecdc c\u01a1 s\u1edf, c\u00e1c kh\u1ed1i ki\u1ebfn th\u1ee9c to\u00e1n h\u1ecdc \u0111\u01b0\u1ee3c m\u1edf r\u1ed9ng v\u00e0 n\u00e2ng cao h\u01a1n r\u1ea5t nhi\u1ec1u so v\u1edbi ch\u01b0\u01a1ng tr\u00ecnh ti\u1ec3u h\u1ecdc tr\u01b0\u1edbc \u0111\u00e2y. B\u1edfi v\u1eady, c\u00e1c b\u00e0i to\u00e1n kh\u00f4ng ch\u1ec9 c\u00f2n d\u1eebng l\u1ea1i \u1edf t\u01b0 duy v\u1ec1 t\u00ednh nh\u1ea9m c\u00e1c ph\u00e9p to\u00e1n \u0111\u01a1n gi\u1ea3n. Hay v\u1ec1 v\u1ebd h\u00ecnh v\u00e0 \u0111\u1ebfm h\u00ecnh nh\u01b0 tr\u01b0\u1edbc. To\u00e1n h\u1ecdc trung h\u1ecdc c\u01a1 s\u1edf hay to\u00e1n l\u1edbp 6 ph\u1ee9c t\u1ea1p h\u01a1n r\u1ea5t nhi\u1ec1u. V\u00ec v\u1eady, \u0111\u1ec3 tr\u00e1nh sai s\u00f3t, nh\u1ea7m l\u1eabn v\u00e0 c\u00f3 th\u1ec3 c\u1ea3i thi\u1ec7n t\u01b0 duy qua m\u00f4n h\u1ecdc n\u00e0y. Tr\u1ebb bu\u1ed9c ph\u1ea3i r\u00e8n luy\u1ec7n, trau d\u1ed3i kh\u00f4ng ng\u1eebng n\u0103ng l\u1ef1c t\u00ednh to\u00e1n, tr\u00ecnh b\u00e0y b\u00e0i logic. V\u00e0 b\u00ean c\u1ea1nh \u0111\u00f3 l\u00e0 c\u1ea3 t\u01b0 duy nh\u1ea1y b\u00e9n v\u1edbi c\u00e1c d\u1ea1ng to\u00e1n m\u1edbi\u2026<\/p>\n\n\n\n Th\u1ee9 2, luy\u1ec7n t\u1eadp th\u1eadt nhi\u1ec1u, n\u00e2ng cao n\u0103ng l\u1ef1c.<\/p>\n\n\n\n \u0110\u1ec3 d\u1ec5 d\u00e0ng chinh ph\u1ee5c m\u00f4n to\u00e1n v\u00e0 tr\u00e1nh vi\u1ec7c l\u00fang t\u00fang trong thi c\u1eed, ki\u1ec3m tra. Con c\u1ea7n \u00f4n luy\u1ec7n th\u1eadt nhi\u1ec1u \u0111\u1ec3 c\u00f3 th\u1ec3 n\u1eafm v\u1eefng l\u00fd thuy\u1ebft v\u00e0 b\u00e0i t\u1eadp. B\u1eaft \u0111\u1ea7u t\u1eeb nh\u1eefng b\u00e0i to\u00e1n c\u01a1 b\u1ea3n, c\u00e1c con c\u1ea7n l\u00e0m nhu\u1ea7n nhuy\u1ec5n \u0111\u1ec3 quen v\u1edbi c\u00e1ch tr\u00ecnh b\u00e0y v\u00e0 x\u00e2y d\u1ef1ng t\u01b0 duy v\u1ec1 d\u1ea1ng b\u00e0i \u0111\u00f3. Sau \u0111\u00f3, m\u1edf r\u1ed9ng d\u1ea7n, gi\u1ea3i quy\u1ebft nh\u1eefng b\u00e0i to\u00e1n ph\u1ee9c t\u1ea1p h\u01a1n. \u0110\u1ec3 con c\u00f3 th\u1ec3 t\u1ef1 tin v\u01b0\u1ee3t qua m\u1ecdi b\u00e0i ki\u1ec3m tra, thi c\u1eed.<\/p>\n\n\n\n B\u00ed quy\u1ebft chinh ph\u1ee5c m\u00f4n to\u00e1n l\u1edbp 6<\/p>\n\n\n\n Th\u1ee9 3, t\u00ecm m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p ph\u00f9 h\u1ee3p \u0111\u1ec3 h\u1ecdc t\u1eadp<\/p>\n\n\n\n T\u00ecm m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p h\u1ecdc t\u1eadp l\u00e0 \u0111i\u1ec1u v\u00f4 c\u00f9ng quan tr\u1ecdng. N\u1ebfu ch\u1ecdn \u0111\u00fang, c\u00e1c con c\u00f3 th\u1ec3 ti\u1ebfn b\u1ed9 r\u1ea5t nhanh. Ng\u01b0\u1ee3c l\u1ea1i, n\u1ebfu ch\u01b0a c\u00f3 ph\u01b0\u01a1ng ph\u00e1p hcoj t\u1eadp c\u1ee5 th\u1ec3, c\u00e1c con s\u1ebd kh\u00f4ng c\u00f3 \u0111\u1ecbnh h\u01b0\u1edbng h\u1ecdc t\u1eadp r\u00f5 r\u00e0ng. B\u1edfi v\u1eady, ba m\u1eb9 c\u00f3 th\u1ec3 ch\u1ecdn cho con c\u00e1c l\u1edbp h\u1ecdc th\u00eam, t\u1ef1 r\u00e8n luy\u1ec7n \u1edf nh\u00e0 ho\u1eb7c c\u00e1c l\u1edbp online. B\u00ean c\u1ea1nh nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p h\u1ea1n ch\u1ebf tr\u1ebb s\u1eed d\u1ee5ng c\u00e1c thi\u1ebft b\u1ecb \u0111i\u1ec7n t\u1eed. Ba m\u1eb9 c\u00f3 th\u1ec3 h\u01b0\u1edbng d\u1eabn con s\u1eed d\u1ee5ng \u0111i\u1ec7n tho\u1ea1i, tivi ph\u1ee5c v\u1ee5 cho vi\u1ec7c h\u1ecdc t\u1eadp. B\u1eb1ng c\u00e1ch \u0111\u0103ng k\u00fd c\u00e1c kh\u00f3a h\u1ecdc online v\u00e0 tr\u1ef1c ti\u1ebfp thep d\u00f5i ti\u1ebfn tr\u00ecnh h\u1ecdc t\u1eadp c\u1ee7a con. Vi\u1ec7c n\u00e0y s\u1ebd gi\u00fap gi\u1ea3m thi\u1ec3u t\u00e1c h\u1ea1i do c\u00e1c con d\u00f9ng thi\u1ebft b\u1ecb di \u0111\u1ed9ng. ph\u00e1t tri\u1ec3n t\u01b0 duy, n\u0103ng l\u1ef1c h\u1ecdc t\u1eadp. Ph\u1ee5 huynh v\u00e0 c\u00e1c con c\u00f3 th\u1ec3 tham kh\u1ea3o th\u00eam 1 s\u1ed1 kh\u00f3a h\u1ecdc online t\u1ea1i Vietlearn. Kh\u00f3a h\u1ecdc \u0111\u00e3 th\u00f4ng qua ki\u1ec3m \u0111\u1ecbnh v\u00e0 mang l\u1ea1i hi\u1ec7u qu\u1ea3 cho r\u1ea5t nhi\u1ec1u h\u1ecdc sinh t\u1ea1i Vi\u1ec7t Nam. \u0110\u00e2y s\u1ebd l\u00e0 m\u1ed9t l\u1ef1a ch\u1ecdn h\u00e0ng \u0111\u1ea7u cho ba m\u1eb9.<\/p>\n\n\n\n L\u1eddi k\u1ebft:<\/p>\n\n\n\n Tr\u00ean \u0111\u00e2y l\u00e0 m\u1ed9t s\u1ed1 chia s\u1ebb c\u1ee7a Vietlearn v\u1ec1 ch\u1ee7 \u0111\u1ec1 to\u00e1n l\u1edbp 6: Quy t\u1eafc chuy\u1ec3n v\u1ebf. Vietlearn hy v\u1ecdng nh\u1eefng th\u00f4ng tin h\u1eefu \u00edch n\u00e0y c\u00f3 th\u1ec3 gi\u00fap con l\u00e0m ch\u1ee7 ki\u1ebfn th\u1ee9c to\u00e1n l\u1edbp 6. H\u00e3y \u0111\u1ec3 l\u1ea1i \u00fd ki\u1ebfn cho Vietlearn t\u1ea1o m\u1ee5c b\u00ecnh lu\u1ead<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":" Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn Quy t\u1eafc chuy\u1ec3n v\u1ebf trong ch\u01b0\u01a1ng tr\u00ecnh to\u00e1n l\u1edbp 6 l\u00e0 m\u1ed9t trong nh\u1eefng b\u00e0i h\u1ecdc c\u01a1 b\u1ea3n. H\u1ecdc sinh c\u1ea7n n\u1eafm v\u1eefng d\u1ea1ng to\u00e1n n\u00e0y. \u0110\u1ec3 c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng v\u00e0 m\u1edf r\u1ed9ng ki\u1ebfn th\u1ee9c trong nh\u1eefng b\u00e0i h\u1ecdc sau. H\u00e3y \u0111\u1ec3 toppy \u0111\u1ed3ng h\u00e0nh c\u00f9ng con chinh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[9,4],"tags":[],"class_list":["post-2765","post","type-post","status-publish","format-standard","hentry","category-toan-hoc","category-trung-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2765","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=2765"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/2765\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=2765"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=2765"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=2765"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}