Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn<\/p>\n\n\n\n
Trung b\u00ecnh c\u1ed9ng l\u00e0 g\u00ec? L\u00e0 m\u1ed9t trong nh\u1eefng ki\u1ebfn th\u1ee9c quan tr\u1ecdng trong ch\u01b0\u01a1ng tr\u00ecnh To\u00e1n<\/a> \u1edf b\u1eadc Ti\u1ec3u h\u1ecdc. Trung b\u00ecnh c\u1ed9ng l\u00e0 ph\u00e9p t\u00ednh l\u1ea5y t\u1ed5ng nhi\u1ec1u s\u1ed1 h\u1ea1ng r\u1ed3i chia cho c\u00e1c s\u1ed1 h\u1ea1ng v\u1eeba l\u1ea5y t\u1ed5ng. C\u00f9ng t\u00ecm hi\u1ec3u chi ti\u1ebft trong n\u1ed9i dung th\u00f4ng tin b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y.<\/p>\n\n\n\n S\u1ed1 trung b\u00ecnh c\u1ed9ng l\u00e0 g\u00ec?<\/p>\n\n\n\n S\u1ed1 trung b\u00ecnh c\u1ed9ng c\u1ee7a m\u1ed9t d\u00e3y s\u1ed1 trong to\u00e1n h\u1ecdc ch\u00ednh l\u00e0 t\u1ec9 s\u1ed1 gi\u1eefa t\u1ed5ng gi\u00e1 tr\u1ecb c\u1ee7a t\u1eadp h\u1ee3p s\u1ed1 \u0111\u00f3 v\u00e0 to\u00e0n b\u1ed9 c\u00e1c ph\u00e2n t\u1eed c\u00f3 trong t\u1eadp h\u1ee3p \u0111\u00f3. Hi\u1ec3u m\u1ed9t c\u00e1ch \u0111\u01a1n gi\u1ea3n nh\u1ea5t v\u1ec1 kh\u00e1i ni\u1ec7m trung b\u00ecnh c\u1ed9ng \u0111\u00f3 l\u00e0 th\u01b0\u01a1ng gi\u1eefa t\u1ed5ng c\u00e1c s\u1ed1 h\u1ea1ng c\u00f3 trong d\u00e3y s\u1ed1 \u0111\u00e3 cho v\u1edbi c\u00e1c s\u1ed1 h\u1ea1ng v\u1eeba l\u1ea5y t\u1ed5ng.<\/p>\n\n\n\n Trung b\u00ecnh c\u1ed9ng c\u1ee7a hai s\u1ed1 l\u00e0 g\u00ec?<\/p>\n\n\n\n Trung b\u00ecnh c\u1ed9ng c\u1ee7a hai s\u1ed1 b\u1eb1ng t\u1ed5ng c\u1ee7a 2 s\u1ed1 \u0111\u00f3 r\u1ed3i chia 2.<\/p>\n\n\n\n V\u00ed d\u1ee5: T\u00ecm trung b\u00ecnh c\u1ed9ng c\u1ee7a s\u1ed1 a v\u00e0 b<\/p>\n\n\n\n => Trung b\u00ecnh c\u1ed9ng c\u1ee7a s\u1ed1 a v\u00e0 b s\u1ebd l\u00e0: (a+b): 2.<\/p>\n\n\n\n \u00dd ngh\u0129a c\u1ee7a s\u1ed1 trung b\u00ecnh c\u1ed9ng l\u00e0 g\u00ec?<\/p>\n\n\n\n D\u1ef1a v\u00e0o s\u1ed1 trung b\u00ecnh c\u1ed9ng m\u00e0 ta c\u00f3 th\u1ec3 t\u00ednh to\u00e1n hay so s\u00e1nh c\u00e1c m\u1eb7t c\u1ee7a \u0111\u1eddi s\u1ed1ng x\u00e3 h\u1ed9i, c\u1ee5 th\u1ec3:<\/p>\n\n\n\n M\u1ee9c thu nh\u1eadp trung b\u00ecnh c\u1ee7a 1 ng\u01b0\u1eddi\/1 th\u00e1ng<\/p>\n\n\n\n Thu nh\u1eadp b\u00ecnh qu\u00e2n \u0111\u1ea7u ng\u01b0\u1eddi c\u1ee7a m\u1ed9t qu\u1ed1c gia \u0111\u1ec3 \u0111\u00e1nh gi\u00e1 s\u1ee9c m\u1ea1nh kinh t\u1ebf c\u1ee7a m\u1ed9t \u0111\u1ea5t n\u01b0\u1edbc \u0111\u00f3.<\/p>\n\n\n\n T\u00ednh tu\u1ed5i th\u1ecd trung b\u00ecnh c\u1ee7a to\u00e0n b\u1ed9 d\u00e2n s\u1ed1 t\u1ea1i m\u1ed9t th\u1eddi \u0111i\u1ec3m nh\u1ea5t \u0111\u1ecbnh.<\/p>\n\n\n\n C\u00f4ng th\u1ee9c t\u00ednh trung b\u00ecnh c\u1ed9ng ch\u00ednh x\u00e1c 100%<\/p>\n\n\n\n C\u00f4ng th\u1ee9c t\u00ednh trung b\u00ecnh c\u1ed9ng nh\u01b0 sau:<\/p>\n\n\n\n Trong \u0111\u00f3:<\/p>\n\n\n\n a l\u00e0 s\u1ed1 trung b\u00ecnh c\u1ed9ng<\/p>\n\n\n\n l\u00e0 s\u1ed1 h\u1ea1ng trong d\u00e3y s\u1ed1<\/p>\n\n\n\n n l\u00e0 s\u1ed1 c\u00e1c s\u1ed1 h\u1ea1ng.<\/p>\n\n\n\n L\u01b0u \u00fd: C\u00e1c s\u1ed1 trong d\u00e3y s\u1ed1 t\u00ednh trung b\u00ecnh c\u1ed9ng ph\u1ea3i l\u00e0 s\u1ed1 th\u1ef1c, kh\u00f4ng \u0111\u01b0\u1ee3c l\u00e0 bi\u1ebfn s\u1ed1<\/p>\n\n\n\n Mu\u1ed1n t\u00ednh trung b\u00ecnh c\u1ed9ng c\u1ee7a nhi\u1ec1u s\u1ed1, b\u1ea1n th\u1ef1c hi\u1ec7n nh\u01b0 sau:<\/p>\n\n\n\n C\u1ed9ng t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 c\u00f3 trong d\u00e3y s\u1ed1 \u0111\u00f3 \u0111\u1ec3 t\u00ecm t\u1ed5ng (b\u1ea1n c\u00f3 th\u1ec3 t\u00ednh nh\u1ea9m ho\u1eb7c s\u1eed d\u1ee5ng m\u00e1y t\u00ednh c\u1ea7m tay)<\/p>\n\n\n\n \u0110\u1ebfm d\u00e3y s\u1ed1 \u0111\u00f3 xem c\u00f3 bao nhi\u00eau s\u1ed1 h\u1ea1ng. Khi c\u00f3 s\u1ed1 l\u1eb7p l\u1ea1i, b\u1ea1n b\u1eaft bu\u1ed9c ph\u1ea3i \u0111\u1ebfm c\u1ea3 s\u1ed1 \u0111\u00f3 v\u00e0 kh\u00f4ng \u0111\u01b0\u1ee3c b\u1ecf qua.<\/p>\n\n\n\n Sau \u0111\u00f3, chia t\u1ed5ng c\u00e1c s\u1ed1 v\u1eeba t\u00ecm \u0111\u01b0\u1ee3c cho s\u1ed1 c\u00e1c s\u1ed1 h\u1ea1ng. Ho\u00e0n th\u00e0nh b\u01b0\u1edbc n\u00e0y l\u00e0 b\u1ea1n \u0111\u00e3 t\u00ecm \u0111\u01b0\u1ee3c s\u1ed1 trung b\u00ecnh c\u1ed9ng.<\/p>\n\n\n\n Quy t\u1eafc t\u00ecm s\u1ed1 trung b\u00ecnh c\u1ed9ng l\u00e0 g\u00ec?<\/p>\n\n\n\n S\u1ed1 trung b\u00ecnh c\u1ed9ng c\u1ee7a m\u1ed9t d\u1ea5u hi\u1ec7u \u0111\u01b0\u1ee3c t\u00ednh t\u1eeb b\u1ea3ng t\u1ea7n s\u1ed1 s\u1ebd theo c\u00e1ch sau:<\/p>\n\n\n\n Nh\u00e2n t\u1eebng gi\u00e1 tr\u1ecb v\u1edbi t\u1ea7n s\u1ed1 t\u01b0\u01a1ng \u1ee9ng<\/p>\n\n\n\n C\u1ed9ng t\u1ea5t c\u1ea3 c\u00e1c t\u00edch b\u1ea1n v\u1eeba t\u00ecm \u0111\u01b0\u1ee3c<\/p>\n\n\n\n Chia t\u1ed5ng cho c\u00e1c gi\u00e1 tr\u1ecb (t\u1ee9c t\u1ed5ng c\u00e1c t\u1ea7n s\u1ed1)<\/p>\n\n\n\n Nguy\u00ean t\u1eafc s\u1eed d\u1ee5ng s\u1ed1 trung b\u00ecnh c\u1ed9ng kh\u00f4ng ph\u1ea3i ai c\u0169ng bi\u1ebft<\/p>\n\n\n\n S\u1ed1 trung b\u00ecnh c\u1ed9ng ch\u1ec9 \u0111\u01b0\u1ee3c t\u00ednh trong m\u1ed9t t\u1ed5ng th\u1ec3 g\u1ed3m nh\u1eefng \u0111\u01a1n v\u1ecb c\u00f3 chung t\u00ednh ch\u1ea5t, thu\u1ed9c m\u1ed9t lo\u1ea1i h\u00ecnh,\u2026<\/p>\n\n\n\n Khi so s\u00e1nh hai t\u1ed5ng th\u1ec3 c\u00f9ng lo\u1ea1i, c\u00f9ng quy m\u00f4 th\u00ec b\u1ea1n ph\u1ea3i d\u00f9ng s\u1ed1 b\u00ecnh qu\u00e2n t\u1ed5 b\u1ed5 sung cho s\u1ed1 b\u00ecnh qu\u00e2n chung.<\/p>\n\n\n\n S\u1eed d\u1ee5ng d\u00e3y s\u1ed1 ph\u00e2n ph\u1ed1i \u0111\u1ec3 b\u1ed5 sung cho s\u1ed1 b\u00ecnh qu\u00e2n chung. Nguy\u00ean t\u1eafc n\u00e0y s\u1ebd \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng cho tr\u01b0\u1eddng h\u1ee3p b\u1ea1n c\u1ea7n so s\u00e1nh 2 \u0111\u1ed1i t\u01b0\u1ee3ng c\u00f9ng lo\u1ea1i nh\u01b0ng c\u00f3 k\u1ebft c\u1ea5u t\u1ed5ng th\u1ec3 kh\u00e1c nhau.<\/p>\n\n\n\n B\u00e0i t\u1eadp d\u1ea1ng 1: Cho d\u00e3y s\u1ed1, y\u00eau c\u1ea7u t\u00ednh trung b\u00ecnh c\u1ed9ng<\/p>\n\n\n\n B\u00e0i t\u1eadp 1: Cho d\u00e3y s\u1ed1 g\u1ed3m c\u00e1c ch\u1eef s\u1ed1: 3, 5, 9, 10, 13. T\u00ednh s\u1ed1 trung b\u00ecnh c\u1ed9ng<\/p>\n\n\n\n G\u1ee3i \u00fd \u0111\u00e1p \u00e1n b\u00e0i t\u1eadp 1:<\/p>\n\n\n\n T\u1ed5ng c\u1ee7a c\u00e1c s\u1ed1 l\u00e0: 3+5+9+10+13 = 40<\/p>\n\n\n\n D\u00e3y s\u1ed1 tr\u00ean c\u00f3 5 s\u1ed1 h\u1ea1ng<\/p>\n\n\n\n => Trung b\u00ecnh c\u1ed9ng c\u1ee7a d\u00e3y s\u1ed1 tr\u00ean = t\u1ed5ng : s\u1ed1 c\u00e1c s\u1ed1 h\u1ea1ng = 40: 5 = 8<\/p>\n\n\n\n B\u00e0i t\u1eadp 2: Kh\u1ed1i 4 c\u1ee7a m\u1ed9t tr\u01b0\u1eddng ti\u1ec3u h\u1ecdc c\u00f3 3 l\u1edbp 4A, 4B, 4C. L\u1edbp 4A c\u00f3 t\u1ed5ng 19 h\u1ecdc sinh<\/a>, l\u1edbp 4B c\u00f3 21 h\u1ecdc sinh<\/a> v\u00e0 l\u1edbp 4C l\u00e0 23 h\u1ecdc sinh<\/a>. H\u1ecfi trung b\u00ecnh m\u1ed7i l\u1edbp c\u00f3 bao nhi\u00eau hoc sinh?<\/p>\n\n\n\n G\u1ee3i \u00fd \u0111\u00e1p \u00e1n b\u00e0i t\u1eadp 2:<\/p>\n\n\n\n S\u1ed1 c\u1ee7a s\u1ed1 h\u1ea1ng \u1edf \u0111\u00e2y l\u00e0 3 v\u00ec c\u00f3 3 l\u1edbp 4A, 4B, 4C<\/p>\n\n\n\n T\u1ed5ng s\u1ed1 h\u1ecdc sinh<\/a> c\u1ee7a 3 l\u1edbp l\u00e0 19+21+23 = 63<\/p>\n\n\n\n => Trung b\u00ecnh s\u1ed1 h\u1ecdc sinh<\/a> c\u1ee7a kh\u1ed1i 4 l\u00e0: 63:3 = 21 (h\u1ecdc sinh<\/a>).<\/p>\n\n\n\n D\u1ea1ng 2: Bi\u1ebft s\u1ed1 trung b\u00ecnh c\u1ed9ng, bi\u1ebft s\u1ed1 h\u1ea1ng, t\u00ecm t\u1ed5ng c\u00e1c s\u1ed1 \u0111\u00f3<\/p>\n\n\n\n \u0110\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c \u0111\u00e1p \u00e1n cho c\u00e1c b\u00e0i t\u1eadp d\u1ea1ng n\u00e0y b\u1ea1n l\u1ea5y trung b\u00ecnh c\u1ed9ng \u0111\u00e3 bi\u1ebft nh\u00e2n v\u1edbi s\u1ed1 c\u00e1c s\u1ed1 d\u1ea1ng.<\/p>\n\n\n\n B\u00e0i t\u1eadp 1: Bi\u1ebft tu\u1ed5i trung b\u00ecnh c\u1ee7a 30 h\u1ecdc sinh l\u1edbp 4 l\u00e0 9 tu\u1ed5i. N\u1ebfu t\u00ednh c\u1ea3 c\u00f4 gi\u00e1o d\u1ea1y to\u00e1n th\u00ec tu\u1ed5i trung b\u00ecnh c\u1ee7a 30 h\u1ecdc sinh l\u00e0 10 tu\u1ed5i. H\u1ecfi c\u00f4 gi\u00e1o d\u1ea1y to\u00e1n bao nhi\u00eau tu\u1ed5i?<\/p>\n\n\n\n G\u1ee3i \u00fd \u0111\u00e1p \u00e1n b\u00e0i t\u1eadp 1:<\/p>\n\n\n\n T\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a 30 h\u1ecdc sinh: 9\u00d730 = 270 tu\u1ed5i<\/p>\n\n\n\n S\u1ed1 ng\u01b0\u1eddi trong l\u1edbp l\u00e0 30 + 1 =31 (ng\u01b0\u1eddi)<\/p>\n\n\n\n T\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a 31 ng\u01b0\u1eddi l\u00e0 10 x 31 = 310 (tu\u1ed5i)<\/p>\n\n\n\n => S\u1ed1 tu\u1ed5i c\u1ee7a c\u00f4 gi\u00e1o d\u1ea1y to\u00e1n l\u00e0 310 \u2013 270 = 40 tu\u1ed5i.<\/p>\n\n\n\n B\u00e0i t\u1eadp s\u1ed1 2: Trung b\u00ecnh c\u1ed9ng c\u1ee7a t\u00e1m s\u1ed1 l\u00e0 12, do th\u00eam s\u1ed1 th\u1ee9 9 n\u00ean trung b\u00ecnh c\u1ed9ng l\u00e0 13. T\u00ecm s\u1ed1 th\u1ee9 9 ?<\/p>\n\n\n\n G\u1ee3i \u00fd l\u1eddi gi\u1ea3i b\u00e0i t\u1eadp 2:<\/p>\n\n\n\n T\u1ed5ng c\u1ee7a t\u00e1m s\u1ed1 l\u00fac \u0111\u1ea7u: 12 x 8 = 96<\/p>\n\n\n\n T\u1ed5ng c\u1ee7a ch\u00edn s\u1ed1: 13 x 9 = 117<\/p>\n\n\n\n => S\u1ed1 th\u1ee9 ch\u00edn s\u1ebd l\u00e0 117 \u2013 96 = 21.<\/p>\n\n\n\n D\u1ea1ng 3: T\u00ednh trung b\u00ecnh c\u1ed9ng c\u1ee7a d\u00e3y s\u1ed1 c\u00e1ch \u0111\u1ec1u<\/p>\n\n\n\n \u0110\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c \u0111\u00e1p \u00e1n cho d\u1ea1ng b\u00e0i t\u00ednh trung b\u00ecnh c\u1ed9ng n\u00e0y b\u1ea1n th\u1ef1c hi\u1ec7n nh\u01b0 sau:<\/p>\n\n\n\n T\u00ecm trung b\u00ecnh c\u1ed9ng c\u1ee7a s\u1ed1 \u0111\u1ea7u, s\u1ed1 cu\u1ed1i<\/p>\n\n\n\n Khi th\u1ea5y d\u00e3y s\u1ed1 c\u00f3 c\u00e1c s\u1ed1 h\u1ea1ng l\u00e0 1 s\u1ed1 l\u1ebb, th\u00ec s\u1ed1 trung b\u00ecnh c\u1ed9ng s\u1ebd l\u00e0 s\u1ed1 \u1edf ch\u00ednh gi\u1eefa d\u00e3y s\u1ed1 \u0111\u00f3. C\u00f2n n\u1ebfu l\u00e0 s\u1ed1 ch\u1eb5n th\u00ec s\u1ed1 trung b\u00ecnh c\u1ed9ng s\u1ebd l\u00e0 1\/2 t\u1ed5ng c\u1ee7a 2 s\u1ed1 \u0111\u1ea7u v\u00e0 s\u1ed1 cu\u1ed1i. N\u1ebfu d\u00e3y s\u1ed1 \u0111\u00e3 cho c\u00f3 1 s\u1ed1 b\u1eb1ng trung b\u00ecnh c\u1ee7a c\u00e1c s\u1ed1 c\u00f2n l\u1ea1i th\u00ec s\u1ed1 \u0111\u00f3 s\u1ebd b\u1eb1ng trung b\u00ecnh c\u1ed9ng c\u1ee7a c\u00e1c s\u1ed1 \u0111\u00e3 cho.<\/p>\n\n\n\n B\u00e0i t\u1eadp s\u1ed1 1: Trung b\u00ecnh c\u1ed9ng c\u1ee7a 10 s\u1ed1 l\u00e0 50. N\u1ebfu l\u1ea5y s\u1ed1 th\u1ee9 nh\u1ea5t c\u1ed9ng v\u1edbi 1, s\u1ed1 th\u1ee9 hai c\u1ed9ng v\u1edbi 2,\u2026s\u1ed1 th\u1ee9 10 c\u1ed9ng v\u1edbi 10 th\u00ec trung b\u00ecnh c\u1ed9ng c\u1ee7a 10 s\u1ed1 m\u1edbi l\u00e0 bao nhi\u00eau?<\/p>\n\n\n\n G\u1ee3i \u00fd \u0111\u00e1p \u00e1n b\u00e0i t\u1eadp 1:<\/p>\n\n\n\n T\u1ed5ng t\u0103ng th\u00eam l\u00e0 1 + 2 + 3 +\u2026.+10 = 50<\/p>\n\n\n\n Trung b\u00ecnh c\u1ed9ng t\u0103ng th\u00eam s\u1ebd l\u00e0: 55 : 10 = 5,5<\/p>\n\n\n\n => Trung b\u00ecnh c\u1ed9ng s\u1ed1 m\u1edbi l\u00e0 50 + 5,5 = 55,5<\/p>\n\n\n\n B\u00e0i t\u1eadp s\u1ed1 2: Cho d\u00e3y s\u1ed1 2, 4, 6, 8, 10, 12. Trong \u0111\u00f3, c\u00f3 4 s\u1ed1 c\u00f3 trung b\u00ecnh c\u1ed9ng b\u1eb1ng 8, t\u00ednh trung b\u00ecnh c\u1ed9ng c\u1ee7a c\u00e1c s\u1ed1 c\u00f2n l\u1ea1i?<\/p>\n\n\n\n G\u1ee3i \u00fd \u0111\u00e1p \u00e1n b\u00e0i t\u1eadp 2:<\/p>\n\n\n\n T\u1ed5ng 6 s\u1ed1 l\u00e0: 2 + 4 + 6 +8 + 10+ 12 = 42<\/p>\n\n\n\n T\u1ed5ng 4 s\u1ed1 l\u00e0: 4 x 8 = 32<\/p>\n\n\n\n T\u1ed5ng 2 s\u1ed1 c\u00f2n l\u1ea1i: 42 \u2013 32 = 10<\/p>\n\n\n\n => Trung b\u00ecnh c\u1ed9ng c\u1ee7a 2 s\u1ed1 c\u00f2n l\u1ea1i l\u00e0 10 : 2 = 5<\/p>\n\n\n\n Mong r\u1eb1ng, n\u1ed9i dung th\u00f4ng tin trong b\u00e0i vi\u1ebft \u201cTrung b\u00ecnh c\u1ed9ng l\u00e0 g\u00ec? C\u00f4ng th\u1ee9c t\u00ednh trung b\u00ecnh c\u1ed9ng ch\u00ednh x\u00e1c 100%\u201d s\u1ebd gi\u00fap \u00edch b\u1ea1n. N\u1ebfu c\u00f3 b\u1ea5t k\u1ef3 \u0111\u00f3ng g\u00f3p n\u00e0o cho b\u00e0i vi\u1ebft, qu\u00fd b\u1ea1n \u0111\u1ecdc h\u00e3y comment ph\u00eda d\u01b0\u1edbi, ch\u00fang t\u00f4i s\u1ebd t\u1ed5ng h\u1ee3p v\u00e0 g\u1eedi \u0111\u1ebfn b\u1ea1n \u0111\u1ecdc trong th\u1eddi gian s\u1edbm nh\u1ea5t!<\/p>\n\n\n\n <\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":" Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn Trung b\u00ecnh c\u1ed9ng l\u00e0 g\u00ec? L\u00e0 m\u1ed9t trong nh\u1eefng ki\u1ebfn th\u1ee9c quan tr\u1ecdng trong ch\u01b0\u01a1ng tr\u00ecnh To\u00e1n \u1edf b\u1eadc Ti\u1ec3u h\u1ecdc. Trung b\u00ecnh c\u1ed9ng l\u00e0 ph\u00e9p t\u00ednh l\u1ea5y t\u1ed5ng nhi\u1ec1u s\u1ed1 h\u1ea1ng r\u1ed3i chia cho c\u00e1c s\u1ed1 h\u1ea1ng v\u1eeba l\u1ea5y t\u1ed5ng. C\u00f9ng t\u00ecm hi\u1ec3u chi ti\u1ebft trong n\u1ed9i dung […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[1],"tags":[],"class_list":["post-3983","post","type-post","status-publish","format-standard","hentry","category-general"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/3983","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=3983"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/3983\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=3983"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=3983"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=3983"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}