Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn<\/p>\n\n\n\n
H\u00f3a h\u1ecdc th\u01b0\u1eddng l\u00e0 n\u1ed7i \u00e1m \u1ea3nh c\u1ee7a kh\u00f4ng \u00edt h\u1ecdc sinh<\/a> khi l\u00ean c\u1ea5p 3. \u0110\u01a1n gi\u1ea3n b\u1edfi b\u1ea1n \u0111\u00e3 kh\u00f4ng bi\u1ebft c\u00e1ch h\u1ecdc v\u00e0 ghi nh\u1edb nh\u1eefng ki\u1ebfn th\u1ee9c c\u01a1 b\u1ea3n<\/a> ngay t\u1eeb ban \u0111\u1ea7u \u0111\u1eb7c bi\u1ec7t l\u00e0 v\u1ec1 c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc. Sau \u0111\u00e2y s\u1ebd l\u00e0 t\u1ed5ng h\u1ee3p c\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 c\u1ea7n nh\u1edb \u0111\u1ec3 gi\u00fap b\u1ea1n c\u00f3 c\u00e1i nh\u00ecn to\u00e0n di\u1ec7n nh\u1ea5t v\u1ec1 n\u1ec1n t\u1ea3ng h\u00f3a h\u1ecdc \u0111\u1ec3 \u00e1p d\u1ee5ng v\u00e0o h\u1ecdc \u1edf nh\u1eefng n\u0103m ti\u1ebfp theo.<\/p>\n\n\n\n C\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 c\u1ea7n nh\u1edb<\/p>\n\n\n\n C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 m\u00e0 b\u1ea1n c\u1ea7n ghi nh\u1edb bao g\u1ed3m c\u00f4ng th\u1ee9c t\u00ednh s\u1ed1 Mol v\u00e0 c\u00f4ng th\u1ee9c t\u00ednh n\u1ed3ng \u0111\u1ed9 dung d\u1ecbch. Sau \u0111\u00e2y s\u1ebd l\u00e0 c\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 c\u1ea7n nh\u1edb c\u1ee5 th\u1ec3.<\/p>\n\n\n\n C\u00f4ng th\u1ee9c t\u00ednh s\u1ed1 Mol<\/p>\n\n\n\n T\u00ednh s\u1ed1 Mo1 theo kh\u1ed1i l\u01b0\u1ee3ng v\u1edbi c\u00f4ng th\u1ee9c:<\/p>\n\n\n\n n = m\/M<\/p>\n\n\n\n Trong \u0111\u00f3:<\/p>\n\n\n\n m: kh\u1ed1i l\u01b0\u1ee3ng<\/p>\n\n\n\n M: kh\u1ed1i l\u01b0\u1ee3ng ph\u00e2n t\u1eed, kh\u1ed1i l\u01b0\u1ee3ng mol<\/p>\n\n\n\n V\u00ed d\u1ee5 1<\/p>\n\n\n\n Cho 2,4 gam Mg v\u00e0o dung d\u1ecbch HCl d\u01b0. T\u00ednh th\u1ec3 t\u00edch kh\u00ed hidro thu \u0111\u01b0\u1ee3c \u1edf \u0111i\u1ec1u ki\u1ec7n<\/p>\n\n\n\n chu\u1ea9n. (Cho Mg=24)<\/p>\n\n\n\n T\u00ednh s\u1ed1 Mol theo th\u1ec3 t\u00edch (\u0111\u1ed1i v\u1edbi ch\u1ea5t kh\u00ed \u1edf \u0111i\u1ec1u ki\u1ec7n chu\u1ea9n):<\/p>\n\n\n\n n =V\/22,4<\/p>\n\n\n\n Trong \u0111\u00f3:<\/p>\n\n\n\n V: th\u1ec3 t\u00edch kh\u00ed<\/p>\n\n\n\n V\u00ed d\u1ee5 2<\/p>\n\n\n\n Cho 6,75 gam kim lo\u1ea1i nh\u00f4m v\u00e0o dung d\u1ecbch H2SO4 lo\u00e3ng . Ph\u1ea3n \u1ee9ng xong thu \u0111\u01b0\u1ee3c<\/p>\n\n\n\n 3,36 l\u00edt kh\u00ed (\u0111ktc).<\/p>\n\n\n\n Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng.<\/p>\n\n\n\n T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng mu\u1ed1i thu \u0111\u01b0\u1ee3c sau ph\u1ea3n \u1ee9ng.<\/p>\n\n\n\n (Cho: Zn = 65; H = 1; S = 32; O = 16)<\/p>\n\n\n\n C\u00f4ng th\u1ee9c t\u00ednh n\u1ed3ng \u0111\u1ed9 dung d\u1ecbch<\/p>\n\n\n\n N\u1ed3ng \u0111\u1ed9 mol \/l\u00edt (CM)<\/p>\n\n\n\n M\u1ed9t trong s\u1ed1 c\u00e1c c\u00f4ng th\u1ee9c c\u1ea7n nh\u1edb ti\u1ebfp theo l\u00e0:<\/p>\n\n\n\n CM =n\/V (M)<\/p>\n\n\n\n Trong \u0111\u00f3:<\/p>\n\n\n\n N: s\u1ed1 mol ch\u1ea5t tan trong dung d\u1ecbch (mol)<\/p>\n\n\n\n V: th\u1ec3 t\u00edch dung d\u1ecbch<\/p>\n\n\n\n C\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 c\u1ea7n nh\u1edb kha\u0301c<\/p>\n\n\n\n \u0110\u0103ng ky\u0301 ho\u0323c th\u01b0\u0309 mi\u00ea\u0303n phi\u0301 m\u00f4n Ho\u0301a ho\u0323c t\u01b0\u0300 l\u01a1\u0301p 8 \u0111\u00ea\u0301n l\u01a1\u0301p 12<\/p><\/blockquote>\n\n\n\n V\u00ed d\u1ee5 3<\/p>\n\n\n\n \u0110\u1ec3 trung h\u00f2a h\u1ebft 200 gam dung d\u1ecbch NaOH 10% c\u1ea7n d\u00f9ng bao nhi\u00eau gam dung d\u1ecbch HCl 3,65%.<\/p>\n\n\n\n (cho Na = 23; Cl = 35,5; O = 16; H = 1)<\/p>\n\n\n\n V\u00ed d\u1ee5 4<\/p>\n\n\n\n Cho 200ml dung d\u1ecbch NaOH 8% c\u00f3 D = 1,15g\/ml t\u00e1c d\u1ee5ng v\u1edbi 380 gam dung d\u1ecbch MgCl2 5%.<\/p>\n\n\n\n Vi\u1ebft PTHH. Ch\u1ea5t n\u00e0o c\u00f2n d\u01b0? T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t d\u01b0.<\/p>\n\n\n\n T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng k\u1ebft t\u1ee7a t\u1ea1o th\u00e0nh. Sau khi lo\u1ea1i b\u1ecf k\u1ebft t\u1ee7a, t\u00ednh C% c\u00e1c ch\u1ea5t c\u00f2n l\u1ea1i sau ph\u1ea3n \u1ee9ng.<\/p>\n\n\n\n Nh\u01b0 v\u1eady c\u00f3 th\u1ec3 t\u1ed5ng h\u1ee3p c\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 c\u1ea7n nh\u1edb nh\u01b0 sau:<\/p>\n\n\n\n 21 c\u00f4ng th\u1ee9c th\u01b0\u1eddng g\u1eb7p trong h\u00f3a h\u1ecdc<\/p>\n\n\n\n Ca\u0301c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc 8 c\u00e2\u0300n nh\u01a1\u0301 theo t\u1eebng chuy\u00ean \u0111\u1ec1 trong SGK<\/p>\n\n\n\n Trong SGK H\u00f3a h\u1ecdc 8 c\u00f3 4 chuy\u00ean \u0111\u1ec1 v\u1edbi 4 n\u1ed9i dung kh\u00e1c nhau v\u00e0 c\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u0169ng nh\u01b0 ki\u1ebfn th\u1ee9c tr\u1ecdng t\u00e2m b\u1ea1n c\u1ea7n nh\u1edb l\u00e0:<\/p>\n\n\n\n Ph\u1ea7n 1: Ch\u1ea5t \u2013 Nguy\u00ean t\u1eed<\/p>\n\n\n\n Ki\u1ebfn th\u1ee9c tr\u1ecdng t\u00e2m v\u1ec1 Ch\u1ea5t<\/p>\n\n\n\n Ch\u1ea5t t\u1ed3n t\u1ea1i \u1edf kh\u1eafp n\u01a1i. \u1ede \u0111\u00e2u c\u00f3 v\u1eadt th\u1ec3 th\u00ec \u1edf \u0111\u00f3 c\u00f3 ch\u1ea5t.<\/p>\n\n\n\n V\u1eadt th\u1ec3 s\u1ebd do 1 ho\u1eb7c nhi\u1ec1u ch\u1ea5t t\u1ea1o n\u00ean.<\/p>\n\n\n\n M\u1ed7i ch\u1ea5t s\u1ebd c\u00f3 t\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc v\u00e0 v\u1eadt l\u00fd kh\u00e1c nhau.<\/p>\n\n\n\n H\u1ed7n h\u1ee3p l\u00e0 s\u1ea3n ph\u1ea9m do hai hay nhi\u1ec1u ch\u1ea5t tr\u1ed9n v\u00e0o v\u1edbi nhau.<\/p>\n\n\n\n T\u00e1ch ch\u1ea5t ra kh\u1ecfi h\u1ed7n h\u1ee3p b\u1eb1ng c\u00e1ch d\u1ef1a v\u00e0o t\u00ednh ch\u1ea5t v\u1eadt l\u00fd v\u00e0 h\u00f3a h\u1ecdc c\u1ee7a t\u1eebng ch\u1ea5t.<\/p>\n\n\n\n Ki\u1ebfn th\u1ee9c tr\u1ecdng t\u00e2m v\u1ec1 Nguy\u00ean t\u1eed<\/p>\n\n\n\n Nguy\u00ean t\u1eed l\u00e0 h\u1ea1t v\u00f4 c\u00f9ng nh\u1ecf v\u00e0 trung h\u00f2a v\u1ec1 \u0111i\u1ec7n.<\/p>\n\n\n\n C\u1ea5u t\u1ea1o c\u1ee7a nguy\u00ean t\u1eed s\u1ebd g\u1ed3m: v\u1ecf nguy\u00ean t\u1eed v\u00e0 h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed<\/p>\n\n\n\n H\u1ea1t nh\u00e2n nguy\u00ean t\u1eed g\u1ed3m: h\u1ea1t proton mang \u0111i\u1ec7n t\u00edch d\u01b0\u01a1ng, h\u1ea1t electron mang \u0111i\u1ec7n t\u00edch \u00e2m v\u00e0 h\u1ea1t n\u01a1tron kh\u00f4ng mang \u0111i\u1ec7n.<\/p>\n\n\n\n C\u1ea5u t\u1ea1o c\u1ee7a h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed<\/p>\n\n\n\n \u0110\u1eb7c \u0111i\u1ec3m v\u00e0 c\u00f4ng th\u1ee9c c\u1ee7a h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed<\/p>\n\n\n\n S\u1ed1 proton b\u1eb1ng s\u1ed1 electron v\u00ec th\u1ebf nguy\u00ean t\u1eed trung h\u00f2a v\u1ec1 \u0111i\u1ec7n n\u00ean. C\u00f4ng th\u1ee9c p = e.<\/p>\n\n\n\n Electron lu\u00f4n lu\u00f4n chuy\u1ec3n \u0111\u1ed9ng xung quanh h\u1ea1t nh\u00e2n v\u00e0 ch\u00fang s\u1eafp x\u1ebfp th\u00e0nh t\u1eebng l\u1edbp.<\/p>\n\n\n\n Proton v\u00e0 notron s\u1ebd c\u00f3 c\u00f9ng kh\u1ed1i l\u01b0\u1ee3ng v\u1edbi nhau. C\u00f4ng th\u1ee9c: m (p) = m (n)<\/p>\n\n\n\n Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a electron r\u1ea5t b\u00e9 kh\u00f4ng \u0111\u00e1ng k\u1ec3, N\u00ean kh\u1ed1i l\u01b0\u1ee3ng nguy\u00ean t\u1eed c\u0169ng l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng h\u1ea1t nh\u00e2n v\u1edbi c\u00f4ng th\u1ee9c: m (nguy\u00ean t\u1eed) = m (h\u1ea1t nh\u00e2n)<\/p>\n\n\n\n Ki\u1ebfn th\u1ee9c tr\u1ecdng t\u00e2m v\u1ec1 Nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc<\/p>\n\n\n\n Nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc: L\u00e0 t\u1eadp h\u1ee3p nh\u1eefng nguy\u00ean t\u1eed c\u00f9ng lo\u1ea1i. Ch\u00fang s\u1ebd c\u00f3 c\u00f9ng s\u1ed1 proton trong h\u1ea1t nh\u00e2n. K\u00fd hi\u1ec7u c\u1ee7a c\u00e1c nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc l\u00e0 kh\u00e1c nhau. V\u00ed d\u1ee5: Na, K, S, Cl, Fe<\/p>\n\n\n\n Nguy\u00ean t\u1eed kh\u1ed1i l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a m\u1ed9t nguy\u00ean t\u1eed t\u00ednh b\u1eb1ng \u0111\u01a1n v\u1ecb cacbon. M\u1ed7i nguy\u00ean t\u1eed c\u00f3 m\u1ed9t kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang bi\u1ec7t,<\/p>\n\n\n\n \u0110\u01a1n v\u1ecb cacbon (\u0111vC): 1 \u0111vC = 1\/12 m (Cacbon)<\/p>\n\n\n\n Trong \u0111\u00f3 kh\u1ed1i l\u01b0\u1ee3ng nguy\u00ean t\u1eed C \u2013 m (Cacbon) = 1, 9926. 10 -23<\/p>\n\n\n\n Ph\u1ea7n 2: Ph\u00e2n t\u1eed<\/p>\n\n\n\n Ph\u00e2n t\u1eed ch\u00ednh l\u00e0 \u0111\u1ea1i di\u1ec7n cho m\u1ed9t ch\u1ea5t. Ch\u00fang g\u1ed3m m\u1ed9t s\u1ed1 nguy\u00ean t\u1eed li\u00ean k\u1ebft v\u1edbi nhau v\u00e0 th\u01b0\u1eddng th\u1ec3 hi\u1ec7n t\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc c\u1ee7a ch\u1ea5t \u0111\u00f3.<\/p>\n\n\n\n C\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 c\u1ea7n nh\u1edb c\u1ee7a ph\u00e2n t\u1eed l\u00e0:<\/p>\n\n\n\n \u0110\u01a1n ch\u1ea5t g\u1ed3m m\u1ed9t nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc. V\u00ed d\u1ee5: H2, O2\u2026<\/p>\n\n\n\n H\u1ee3p ch\u1ea5t l\u00e0 ch\u1ea5t \u0111\u01b0\u1ee3c t\u1ea1o n\u00ean t\u1eeb hai nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc tr\u1edf l\u00ean. V\u00ed d\u1ee5: NaCl, MnO, H2O\u2026<\/p>\n\n\n\n Nh\u01b0 v\u1eady ch\u00fang ta c\u00f3 c\u00f4ng th\u1ee9c t\u00ednh kh\u1ed1i l\u01b0\u1ee3ng ph\u00e2n t\u1eed nh\u01b0 sau:<\/p>\n\n\n\n Ph\u00e2n t\u1eed kh\u1ed1i = kh\u1ed1i l\u01b0\u1ee3ng ph\u00e2n t\u1eed (\u0111vC) = t\u1ed5ng s\u1ed1 nguy\u00ean t\u1eed nguy\u00ean t\u1ed1 . nguy\u00ean t\u1eed kh\u1ed1i<\/p>\n\n\n\n B\u00e2\u0323t mi\u0301 ca\u0301ch \u0111a\u0301nh bay n\u00f4\u0303i s\u01a1\u0323 m\u00f4n Ho\u0301a ho\u0323c \u2013 Vietlearn<\/p><\/blockquote>\n\n\n\n Ph\u1ea7n 3: C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc<\/p>\n\n\n\n C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u0169ng l\u00e0 m\u1ed9t nh\u00f3m ki\u1ebfn th\u1ee9c v\u00f4 c\u00f9ng quan tr\u1ecdng c\u1ee7a l\u1edbp 8. C\u00e1c c\u00f4ng th\u1ee9c c\u1ea7n nh\u1edb v\u00e0 ki\u1ebfn th\u1ee9c c\u1ee7a ph\u1ea7n n\u00e0y l\u00e0:<\/p>\n\n\n\n C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a m\u1ed9t \u0111\u01a1n ch\u1ea5t s\u1ebd \u0111\u01b0\u1ee3c k\u00ed hi\u1ec7u d\u01b0\u1edbi 2 d\u1ea1ng l\u00e0 A v\u00e0 Ax. Trong \u0111\u00f3<\/p>\n\n\n\n A l\u00e0 \u0111\u01a1n ch\u1ea5t kim lo\u1ea1i v\u00e0 m\u1ed9t v\u00e0i phi kim. V\u00ed d\u1ee5 nh\u01b0: Na, Fe, Cu, P, C, S<\/p>\n\n\n\n Ax l\u00e0 \u0111\u01a1n ch\u1ea5t phi kim s\u1ebd bao g\u1ed3m 2 nguy\u00ean t\u1eed li\u00ean k\u1ebft v\u1edbi nhau nh\u01b0: O2, H2, N2<\/p>\n\n\n\n C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c h\u1ee3p ch\u1ea5t l\u00e0: AxByCz<\/p>\n\n\n\n Trong \u0111\u00f3:<\/p>\n\n\n\n A, B, C: c\u00e1c k\u00ed hi\u1ec7u h\u00f3a h\u1ecdc<\/p>\n\n\n\n x, y, z l\u00e0 c\u00e1c ch\u1ec9 s\u1ed1 ch\u00e2n cho b\u1ea1n bi\u1ebft v\u1ec1 s\u1ed1 nguy\u00ean t\u1eed c\u1ee7a nguy\u00ean t\u1ed1 \u0111\u00f3 c\u00f3 trong m\u1ed9t ph\u00e2n t\u1eed l\u00e0 bao nhi\u00eau<\/p>\n\n\n\n Ph\u1ea7n 4: H\u00f3a tr\u1ecb<\/p>\n\n\n\n H\u00f3a tr\u1ecb c\u1ee7a m\u1ed9t ho\u1eb7c m\u1ed9t nh\u00f3m nguy\u00ean t\u1ed1 l\u00e0 con s\u1ed1 \u0111\u01b0\u1ee3c vi\u1ebft b\u00ean c\u1ea1nh t\u00ean c\u1ee7a nguy\u00ean t\u1ed1 \u0111\u00f3. Ch\u00fang bi\u1ec3u th\u1ecb cho kh\u1ea3 n\u0103ng li\u00ean k\u1ebft c\u1ee7a c\u00e1c nguy\u00ean t\u1eed ho\u1eb7c nh\u00f3m nguy\u00ean t\u1eed \u0111\u00f3.<\/p>\n\n\n\n Quy t\u1eafc h\u00f3a tr\u1ecb: AxBy -> a.x = b.y<\/p>\n\n\n\n Trong \u0111\u00f3<\/p>\n\n\n\n a, b l\u00e0 h\u00f3a tr\u1ecb c\u1ee7a nguy\u00ean t\u1ed1.<\/p>\n\n\n\n x, y l\u00e0 ch\u1ec9 s\u1ed1 hay s\u1ed1 nguy\u00ean t\u1eed c\u1ee7a nguy\u00ean t\u1ed1<\/p>\n\n\n\n Tr\u00ean \u0111\u00e2y l\u00e0 c\u00e1c c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u1edbp 8 c\u1ea7n nh\u1edb hy v\u1ecdng \u0111\u00e3 c\u00f3 th\u1ec3 gi\u00fap b\u1ea1n kh\u00e1i qu\u00e1t l\u1ea1i to\u00e0n b\u1ed9 ki\u1ebfn th\u1ee9c m\u00f4n h\u00f3a l\u1edbp 8 \u0111\u1ec3 b\u1ea1n h\u1ecdc t\u1eadp<\/a> d\u1ec5 d\u00e0ng h\u01a1n.<\/p>\n\n\n\n <\/p>\n\n\n\n T\u00ednh ch\u1ea5t v\u1eadt l\u00fd c\u1ee7a Kim lo\u1ea1i \u2013 H\u1ecdc t\u1ed1t H\u00f3a 9<\/p>\n\n\n\n D\u00e3y ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc c\u1ee7a kim lo\u1ea1i \u0111\u1ea7y<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":" Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn H\u00f3a h\u1ecdc th\u01b0\u1eddng l\u00e0 n\u1ed7i \u00e1m \u1ea3nh c\u1ee7a kh\u00f4ng \u00edt h\u1ecdc sinh khi l\u00ean c\u1ea5p 3. \u0110\u01a1n gi\u1ea3n b\u1edfi b\u1ea1n \u0111\u00e3 kh\u00f4ng bi\u1ebft c\u00e1ch h\u1ecdc v\u00e0 ghi nh\u1edb nh\u1eefng ki\u1ebfn th\u1ee9c c\u01a1 b\u1ea3n ngay t\u1eeb ban \u0111\u1ea7u \u0111\u1eb7c bi\u1ec7t l\u00e0 v\u1ec1 c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc. Sau \u0111\u00e2y s\u1ebd l\u00e0 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[8,4],"tags":[],"class_list":["post-750","post","type-post","status-publish","format-standard","hentry","category-hoa-hoc","category-trung-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/750","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=750"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/750\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=750"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=750"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=750"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}