C\u1ea5p m\u1ed9t l\u00e0 c\u1ea5p th\u1ea5p nh\u1ea5t, c\u1ea5p hai cao h\u01a1n c\u1ea5p m\u1ed9t v\u00e0 c\u1ea5p ba l\u00e0 c\u1ea5p cao nh\u1ea5t. Th\u1ee9 t\u1ef1 ti\u1ebfn h\u00e0nh c\u00e1c ph\u00e9p to\u00e1n c\u00f3 li\u00ean quan ch\u1eb7t ch\u1ebd v\u1edbi c\u00e1c c\u1ea5p c\u1ee7a c\u00e1c ph\u00e9p to\u00e1n. V\u1edbi c\u00e1c ph\u00e9p to\u00e1n \u0111\u1ed3ng c\u1ea5p th\u00ec \u01b0u ti\u00ean theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00e1i sang ph\u1ea3i. C\u00f2n c\u00e1c ph\u00e9p to\u00e1n kh\u00f4ng \u0111\u1ed3ng c\u1ea5p th\u00ec th\u1ef1c hi\u1ec7n \u01b0u ti\u00ean t\u1eeb c\u1ea5p cao \u0111\u1ebfn c\u1ea5p th\u1ea5p.<\/p>\n\n\n\n
V\u00ec sao l\u1ea1i ph\u1ea3i chia c\u00e1c ph\u00e9p to\u00e1n s\u1ed1 h\u1ecdc th\u00e0nh ba c\u1ea5p?<\/p>\n\n\n\n
Trong ph\u00e9p to\u00e1n s\u1ed1 h\u1ecdc c\u00f3 5 quy t\u1eafc trong th\u1ef1c hi\u1ec7n c\u00e1c ph\u00e9p to\u00e1n: Lu\u1eadt k\u1ebft h\u1ee3p, lu\u1eadt giao ho\u00e1n trong ph\u00e9p c\u1ed9ng, lu\u1eadt giao ho\u00e1n v\u00e0 k\u1ebft h\u1ee3p trong khi th\u1ef1c hi\u1ec7n ph\u00e9p nh\u00e2n, lu\u1eadt ph\u00e2n b\u1ed1 khi th\u1ef1c hi\u1ec7n ph\u00e9p nh\u00e2n k\u1ebft h\u1ee3p ph\u00e9p c\u1ed9ng. Tr\u01b0\u1edbc h\u1ebft ta xem x\u00e9t lu\u1eadt ph\u00e2n b\u1ed1 khi k\u1ebft h\u1ee3p ph\u00e9p c\u1ed9ng v\u1edbi ph\u00e9p nh\u00e2n: (a + b) x c = a x c + b x c ph\u00e9p nh\u00e2n c\u0169ng c\u00f3 lu\u1eadt ph\u00e2n b\u1ed1 khi k\u1ebft h\u1ee3p v\u1edbi ph\u00e9p tr\u1eeb (a – b) x c = a x c – b x c<\/p>\n\n\n\n
Ph\u00e9p chia c\u0169ng c\u00f3 lu\u1eadt ph\u00e2n b\u1ed1 khi k\u1ebft h\u1ee3p v\u1edbi ph\u00e9p c\u1ed9ng v\u00e0 ph\u00e9p tr\u1eeb<\/p>\n\n\n\n
T\u1eeb \u0111\u00f3 c\u00f3 th\u1ec3 kh\u00e1i qu\u00e1t ph\u00e9p t\u00ednh c\u1ea5p hai c\u00f3 t\u00ednh ch\u1ea5t ph\u00e2n b\u1ed1 v\u1edbi c\u00e1c ph\u00e9p t\u00ednh c\u1ea5p m\u1ed9t.<\/p>\n\n\n\n
Ch\u00fang ta \u0111\u1ec1u bi\u1ebft ph\u00e9p t\u00ednh tr\u1eeb ch\u00ednh l\u00e0 ph\u00e9p c\u1ed9ng v\u1edbi m\u1ed9t s\u1ed1 tr\u00e1i d\u1ea5u. V\u00ed d\u1ee5 3 – 2 = 3 +(-2). Nh\u01b0 v\u1eady ph\u00e9p t\u00ednh tr\u1eeb c\u00f3 th\u1ec3 quy v\u1ec1 ph\u00e9p t\u00ednh c\u1ed9ng. C\u00f2n ph\u00e9p chia ch\u00ednh l\u00e0 ph\u00e9p nh\u00e2n v\u1edbi m\u1ed9t ngh\u1ecbch \u0111\u1ea3o c\u1ee7a m\u1ed9t s\u1ed1. V\u00ed d\u1ee5: 3: 2 = 3 x 1\/2<\/p>\n\n\n\n
V\u1eady v\u1edbi ph\u00e9p t\u00ednh chia ta c\u00f3 th\u1ec3 quy v\u1ec1 ph\u00e9p t\u00ednh nh\u00e2n. V\u00ec v\u1eady t\u00ednh ch\u1ea5t ph\u00e2n b\u1ed1 c\u1ee7a ph\u00e9p t\u00ednh nh\u00e2n v\u1edbi ph\u00e9p t\u00ednh c\u1ed9ng l\u00e0 m\u1ed9t quy lu\u1eadt c\u00f3 t\u00ednh c\u01a1 b\u1ea3n trong khi ti\u1ebfn h\u00e0nh t\u00ednh to\u00e1n.<\/p>\n\n\n\n
R\u00f5 r\u00e0ng l\u00e0 (ab)n = anbn<\/p>\n\n\n\n
Nh\u01b0 (3.2)4 = (3.2).(3.2).(3.2).(3.2) = (3.3.3.3).(2.2.2.2) = 34.24<\/p>\n\n\n\n
V\u00ec v\u1eady ph\u00e9p t\u00ednh lu\u1ef9 th\u1eeba c\u0169ng th\u1ec3 hi\u1ec7n lu\u1eadt ph\u00e2n b\u1ed1 v\u1edbi ph\u00e9p t\u00ednh nh\u00e2n. T\u01b0\u01a1ng t\u1ef1 ph\u00e9p t\u00ednh lu\u1ef9 th\u1eeba c\u0169ng c\u00f3 t\u00ednh ch\u1ea5t ph\u00e2n b\u1ed1 v\u1edbi ph\u00e9p t\u00ednh chia (a: b)n = an: bn<\/p>\n\n\n\n
V\u00ec v\u1eady ta th\u1ea5y c\u00e1c ph\u00e9p t\u00ednh c\u1ea5p ba th\u1ec3 hi\u1ec7n lu\u1eadt ph\u00e2n b\u1ed1 v\u1edbi ph\u00e9p t\u00ednh c\u1ea5p hai. Ta c\u00f3 th\u1ec3 ti\u1ebfn l\u00ean kh\u00e1i qu\u00e1t cao h\u01a1n m\u1ed9t b\u01b0\u1edbc. C\u00e1c ph\u00e9p to\u00e1n cao h\u01a1n m\u1ed9t c\u1ea5p th\u1ec3 hi\u1ec7n lu\u1eadt ph\u00e2n b\u1ed1 cho c\u00e1c ph\u00e9p to\u00e1n c\u1ea5p th\u1ea5p h\u01a1n m\u1ed9t c\u1ea5p. Khi \u0111\u00e3 nh\u1eadn th\u1ee9c \u0111\u01b0\u1ee3c c\u00e1c c\u1ea5p c\u1ee7a ph\u00e9p t\u00ednh s\u1ed1 h\u1ecdc ta c\u00f3 th\u1ec3 nhanh ch\u00f3ng ti\u1ebfn h\u00e0nh ch\u00ednh x\u00e1c c\u00e1c ph\u00e9p to\u00e1n s\u1ed1 h\u1ecdc. C\u00f3 \u0111i\u1ec1u c\u1ea7n ch\u00fa \u00fd l\u00e0 c\u00e1c ph\u00e9p t\u00ednh s\u1ed1 h\u1ecdc c\u1ea5p ba kh\u00f4ng c\u00f3 lu\u1eadt ph\u00e2n b\u1ed1 v\u1edbi c\u00e1c ph\u00e9p to\u00e1n c\u1ea5p m\u1ed9t.<\/p>\n\n\n\n
T\u1eeb kho\u00e1: Th\u1ee9 t\u1ef1 th\u1ef1c hi\u1ec7n c\u00e1c ph\u00e9p t\u00ednh s\u1ed1 h\u1ecdc.<\/p>\n\n\n\n
<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":"
C\u1ea5p m\u1ed9t l\u00e0 c\u1ea5p th\u1ea5p nh\u1ea5t, c\u1ea5p hai cao h\u01a1n c\u1ea5p m\u1ed9t v\u00e0 c\u1ea5p ba l\u00e0 c\u1ea5p cao nh\u1ea5t. Th\u1ee9 t\u1ef1 ti\u1ebfn h\u00e0nh c\u00e1c ph\u00e9p to\u00e1n c\u00f3 li\u00ean quan ch\u1eb7t ch\u1ebd v\u1edbi c\u00e1c c\u1ea5p c\u1ee7a c\u00e1c ph\u00e9p to\u00e1n. V\u1edbi c\u00e1c ph\u00e9p to\u00e1n \u0111\u1ed3ng c\u1ea5p th\u00ec \u01b0u ti\u00ean theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00e1i sang ph\u1ea3i. C\u00f2n […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[15,9],"tags":[],"class_list":["post-7521","post","type-post","status-publish","format-standard","hentry","category-hoi-dap-khoa-hoc","category-toan-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/7521","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=7521"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/7521\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=7521"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=7521"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=7521"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}