N\u1ebfu ch\u00fa \u00fd quan s\u00e1t \u0111\u00e0n c\u00e1 b\u01a1i l\u1ed9i trong b\u1ec3 c\u00e1 b\u1ea1n s\u1ebd th\u1ea5y ch\u00fang lu\u00f4n l\u00fac n\u1ed5i l\u00ean l\u00fac l\u1eb7n xu\u1ed1ng. \u0110\u00f3 ch\u00ednh l\u00e0 c\u00e1ch c\u00e1 th\u1ef1c hi\u1ec7n vi\u1ec7c ti\u1ebft ki\u1ec7m n\u0103ng l\u01b0\u1ee3ng. Th\u1ebf t\u1ea1i sao c\u00e1ch b\u01a1i l\u1ed9i n\u00e0y l\u1ea1i ti\u1ebft ki\u1ec7m \u0111\u01b0\u1ee3c n\u0103ng l\u01b0\u1ee3ng?<\/p>\n\n\n\n
Gi\u1ea3 s\u1eed c\u00e1 b\u01a1i v\u1edbi t\u1ed1c \u0111\u1ed9 kh\u00f4ng \u0111\u1ed5i v. Cho D l\u00e0 l\u1ef1c c\u1ea3n m\u00e0 c\u00e1 ph\u1ea3i ch\u1ecbu khi l\u1eb7n v\u1edbi t\u1ed1c \u0111\u1ed9 \u0111\u00f3. Cho W l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng t\u0129nh c\u1ee7a c\u00e1, \u03b1 l\u00e0 g\u00f3c l\u1eb7n xu\u1ed1ng c\u1ee7a c\u00e1 so v\u1edbi \u0111\u01b0\u1eddng n\u1eb1m ngang, \u03b2 l\u00e0 g\u00f3c khi c\u00e1 n\u1ed5i l\u00ean.<\/p>\n\n\n\n
Theo c\u01a1 h\u1ecdc khi c\u00e1 l\u1eb7n s\u1ebd ch\u1ecbu l\u1ef1c c\u1ea3n th\u1eb3ng \u0111\u1ee9ng h\u01b0\u1edbng l\u00ean b\u1eb1ng ph\u00e2n l\u1ef1c c\u1ee7a kh\u1ed1i l\u01b0\u1ee3ng t\u0129nh W khi chuy\u1ec3n \u0111\u1ed9ng.<\/p>\n\n\n\n
D = Wsin\u03b1<\/p>\n\n\n\n
Khi c\u00e1 l\u1eb7n l\u1ef1c c\u1ea3n s\u1ebd b\u1eb1ng k l\u1ea7n l\u1ef1c \u0111\u1ea9y t\u1ee9c l\u00e0 b\u1eb1ng kD. Khi c\u00e1 n\u1ed5i l\u00ean s\u1ebd c\u1ea7n m\u1ed9t l\u1ef1c b\u1eb1ng t\u1ed5ng c\u1ee7a l\u1ef1c n\u1ed5i v\u00e0 ph\u00e2n l\u1ef1c c\u1ee7a l\u1ef1c c\u1ea3n h\u01b0\u1edbng l\u00ean do l\u1ef1c \u0111\u1ea9y K v\u1edbi kh\u1ed1i l\u01b0\u1ee3ng t\u0129nh W, t\u1ee9c<\/p>\n\n\n\n
KD + Wsin\u03b2 = W (Ksin\u03b1+ sin\u03b2)<\/p>\n\n\n\n
Khi c\u00e1 l\u1ed9i theo ph\u01b0\u01a1ng n\u1eb1m ngang, ph\u00e2n l\u1ef1c do chuy\u1ec3n \u0111\u1ed9ng h\u01b0\u1edbng l\u00ean b\u1eb1ng 0, l\u1ef1c c\u1ea7n thi\u1ebft s\u1ebd l\u00e0<\/p>\n\n\n\n
KD = WK sin \u03b1<\/p>\n\n\n\n
C\u00f2n khi c\u00e1 l\u1eb7n kh\u00f4ng c\u1ea7n l\u1ef1c. Do \u0111\u00f3 khi c\u00e1 b\u01a1i theo \u0111\u01b0\u1eddng t\u1eeb A \u0111\u1ebfn C l\u1ea1i l\u1eb7n xu\u1ed1ng \u0111i\u1ec3m B theo h\u00ecnh r\u0103ng c\u01b0a so v\u1edbi vi\u1ec7c b\u01a1i theo ph\u01b0\u01a1ng n\u1eb1m ngang AB th\u00ec t\u1ec9 s\u1ed1 n\u0103ng l\u01b0\u1ee3ng ti\u00eau t\u1ed1n cho hai tr\u01b0\u1eddng h\u1ee3p s\u1ebd l\u00e0 (c\u00f4ng \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng t\u00edch s\u1ed1 c\u1ee7a l\u1ef1c nh\u00e2n v\u1edbi \u0111o\u1ea1n \u0111\u01b0\u1eddng \u0111i\u1ec3m \u0111\u1eb7t c\u1ee7a l\u1ef1c d\u1ecbch chuy\u1ec3n):<\/p>\n\n\n\n
M\u00e0 AB = AC cos\u03b2 + CDcotg\u03b1 = AC (cos\u03b2 + sin\u03b2 + cotg\u03b1) N\u00ean<\/p>\n\n\n\n
Theo quan s\u00e1t th\u1ef1c t\u1ebf th\u00ec th\u00f4ng th\u01b0\u1eddng \u03b1 = 11,20o,<\/p>\n\n\n\n
K = 3 n\u00ean<\/p>\n\n\n\n
Theo h\u00ecnh v\u1ebd ta th\u1ea5y 11,2o + \u03b2 < \u03c0\/2 n\u00ean \u03b2 < 78,4o th\u00ec P < 1 t\u1ee9c khi c\u00e1 b\u01a1i l\u1ed9i theo \u0111\u01b0\u1eddng r\u0103ng c\u01b0a th\u00ec ti\u00eau t\u1ed1n \u00edt n\u0103ng l\u01b0\u1ee3ng h\u01a1n khi b\u01a1i ngang. \u0110\u1eb7c bi\u1ec7t khi \u03b2 = 59,15o th\u00ec P = 0,51 n\u00ean khi c\u00e1 b\u01a1i theo h\u00ecnh r\u0103ng c\u01b0a th\u00ec ti\u00eau hao n\u0103ng l\u01b0\u1ee3ng ch\u1ec9 g\u1ea7n b\u1eb1ng n\u1eeda n\u0103ng l\u01b0\u1ee3ng khi c\u00e1 b\u01a1i ngang. Cho n\u00ean, c\u00e1 \u0111\u01b0\u01a1ng nhi\u00ean l\u00e0 b\u01a1i l\u1ed9i theo ki\u1ec3u h\u00ecnh r\u0103ng c\u01b0a.<\/p>\n\n\n\n
T\u1eeb kho\u00e1: L\u1ef1c c\u1ea3n; Ti\u00eau hao n\u0103ng l\u01b0\u1ee3ng; H\u00ecnh r\u0103ng c\u01b0a.<\/p>\n\n\n\n
<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":"
N\u1ebfu ch\u00fa \u00fd quan s\u00e1t \u0111\u00e0n c\u00e1 b\u01a1i l\u1ed9i trong b\u1ec3 c\u00e1 b\u1ea1n s\u1ebd th\u1ea5y ch\u00fang lu\u00f4n l\u00fac n\u1ed5i l\u00ean l\u00fac l\u1eb7n xu\u1ed1ng. \u0110\u00f3 ch\u00ednh l\u00e0 c\u00e1ch c\u00e1 th\u1ef1c hi\u1ec7n vi\u1ec7c ti\u1ebft ki\u1ec7m n\u0103ng l\u01b0\u1ee3ng. Th\u1ebf t\u1ea1i sao c\u00e1ch b\u01a1i l\u1ed9i n\u00e0y l\u1ea1i ti\u1ebft ki\u1ec7m \u0111\u01b0\u1ee3c n\u0103ng l\u01b0\u1ee3ng? Gi\u1ea3 s\u1eed c\u00e1 b\u01a1i v\u1edbi t\u1ed1c \u0111\u1ed9 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[15,9],"tags":[],"class_list":["post-7605","post","type-post","status-publish","format-standard","hentry","category-hoi-dap-khoa-hoc","category-toan-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/7605","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=7605"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/7605\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=7605"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=7605"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=7605"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}