Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn<\/p>\n\n\n\n
L\u00e0m sao \u0111\u1ec3 bi\u1ebft \u0111\u01b0\u1ee3c ch\u1ea5t kh\u00ed n\u00e0o \u0111\u00f3 c\u00f3 nh\u1eefng t\u00ednh ch\u1ea5t g\u00ec? L\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 ch\u00fang ta bi\u1ebft \u0111\u01b0\u1ee3c ch\u1ea5t kh\u00ed \u0111\u00f3 nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00ed Hidro H2, kh\u00ed Oxi O2 hay kh\u00f4ng kh\u00ed. V\u1eady c\u00e2u h\u1ecfi \u0111\u1eb7t ra l\u00e0: T\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed l\u00e0 g\u00ec? T\u1ec9 kh\u1ed1i c\u1ee7a kh\u00f4ng kh\u00ed? C\u00f4ng th\u1ee9c n\u00e0o \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng \u0111\u1ec3 t\u00ednh t\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed? L\u00e0m sao t\u00ednh \u0111\u01b0\u1ee3c t\u1ec9 kh\u1ed1i so v\u1edbi kh\u00f4ng kh\u00ed, v\u1edbi kh\u00ed Oxi hay so v\u1edbi kh\u00ed Hidro? T\u1ea5t c\u1ea3 c\u00e2u h\u1ecfi tr\u00ean s\u1ebd \u0111\u01b0\u1ee3c gi\u1ea3i \u0111\u00e1p qua b\u00e0i sau.<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed<\/p>\n\n\n\n
\u0110\u1ecbnh ngh\u0129a t\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed<\/p>\n\n\n\n
Kh\u00e1i ni\u1ec7m t\u1ec9 kh\u1ed1i ch\u1ec9 s\u1eed d\u1ee5ng cho ch\u1ea5t kh\u00ed. T\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed l\u00e0 c\u00f4ng th\u1ee9c gi\u00fap x\u00e1c \u0111\u1ecbnh ph\u00e2n t\u1eed kh\u1ed1i c\u1ee7a kh\u00ed A so v\u1edbi kh\u00ed B, \u0111\u1ec3 bi\u1ebft ch\u1ea5t kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n ch\u1ea5t kh\u00ed B bao nhi\u00eau l\u1ea7n. C\u00e1ch so s\u00e1nh \u0111\u00f3 l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a hai ch\u1ea5t kh\u00ed \u0111\u00f3 v\u1edbi nhau MA v\u00e0 MB.<\/p>\n\n\n\n
C\u00f4ng th\u1ee9c t\u00ednh<\/p>\n\n\n\n
Trong \u0111\u00f3:<\/p>\n\n\n\n
dA\/B l\u00e0 t\u1ec9 kh\u1ed1i gi\u1eefa kh\u00ed A v\u1edbi kh\u00ed B<\/p>\n\n\n\n
MA l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng mol kh\u00ed A<\/p>\n\n\n\n
MB l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng mol kh\u00ed B<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed<\/p>\n\n\n\n
Tham kha\u0309o: \u01af\u0301ng du\u0323ng ho\u0323c tr\u01b0\u0323c tuy\u00ea\u0301n ha\u0300ng \u0111\u00e2\u0300u Vi\u00ea\u0323t Nam \u2013 Vietlearn<\/p><\/blockquote>\n\n\n\n
Kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00ed B<\/p>\n\n\n\n
C\u00f4ng th\u1ee9c x\u00e1c \u0111\u1ecbnh kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00ed B<\/p>\n\n\n\n
Kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00ed B<\/p>\n\n\n\n
L\u01b0u \u00fd:<\/p>\n\n\n\n
N\u1ebfu dA\/B < 1 suy ra kh\u00ed A nh\u1eb9 h\u01a1n kh\u00ed B<\/p>\n\n\n\n
N\u1ebfu dA\/B = 1 suy ra kh\u00ed A b\u1eb1ng h\u01a1n kh\u00ed B<\/p>\n\n\n\n
N\u1ebfu dA\/B > 1 suy ra kh\u00ed A l\u1edbn h\u01a1n kh\u00ed B<\/p>\n\n\n\n
Kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
Kh\u00f4ng kh\u00ed trong th\u1ef1c t\u1ebf l\u00e0 h\u1ed7n h\u1ee3p c\u1ee7a nhi\u1ec1u kh\u00ed kh\u00e1c nhau, \u0111\u1ec3 \u0111\u01a1n gi\u1ea3n trong t\u00ednh to\u00e1n, ta xem kh\u00f4ng kh\u00ed g\u1ed3m 20% kh\u00ed oxi v\u00e0 80% kh\u00ed nito. Kh\u1ed1i l\u01b0\u1ee3ng mol kh\u00f4ng kh\u00ed (t\u1ee9c 1 mol kh\u00f4ng kh\u00ed) \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 sau:<\/p>\n\n\n\n
Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a 0,2 mol kh\u00ed oxi + 0,8 mol kh\u00ed nit\u01a1<\/p>\n\n\n\n
MKK = (32 x 0,2) + (28 x 0,8) = 28,8 (g\/mol) l\u00e0m tr\u00f2n th\u00e0nh 29 (g\/mol)<\/p>\n\n\n\n
Do \u0111\u00f3, \u0111\u1ec3 bi\u1ebft kh\u00ed A n\u00e0y nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed m\u1ea5y l\u1ea7n, ta s\u1ebd ti\u1ebfn h\u00e0nh so s\u00e1nh kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a kh\u00ed A (MA) \u0111\u1ed1i v\u1edbi kh\u1ed1i l\u01b0\u1ee3ng mol kh\u00f4ng kh\u00ed (Mkk = 29 g\/mol)<\/p>\n\n\n\n
C\u00f4ng th\u1ee9c t\u00ednh t\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed A so v\u1edbi kh\u00f4ng kh\u00ed:<\/p>\n\n\n\n
C\u00f4ng th\u1ee9c t\u00ednh t\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed A so v\u1edbi kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
Trong \u0111\u00f3:<\/p>\n\n\n\n
dA\/KK l\u00e0 t\u1ec9 kh\u1ed1i gi\u1eefa kh\u00ed A v\u1edbi kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
MA l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a kh\u00ed A<\/p>\n\n\n\n
29 l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
Kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
V\u00ed d\u1ee5: Kh\u00ed Hidro (H2) nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed m\u1ea5y l\u1ea7n?<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed H2 so v\u1edbi kh\u00f4ng kh\u00ed l\u00e0:<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed H2 so v\u1edbi kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
K\u1ebft lu\u1eadn: kh\u00ed Hidro (H2) nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed 0,069 l\u1ea7n.<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a h\u1ed7n h\u1ee3p c\u00e1c kh\u00ed<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a h\u1ed7n h\u1ee3p c\u00e1c kh\u00ed<\/p>\n\n\n\n
T\u1ed5ng k\u1ebft ki\u1ebfn th\u1ee9c<\/p>\n\n\n\n
Qua ph\u1ea7n l\u00fd thuy\u1ebft mol t\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed tr\u00ean, b\u1ea1n c\u1ea7n n\u1eafm \u0111\u01b0\u1ee3c n\u1ed9i dung sau:<\/p>\n\n\n\n
1\/ C\u00e1ch x\u00e1c \u0111\u1ecbnh kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00ed B bao nhi\u00eau l\u1ea7n, c\u00f4ng th\u1ee9c t\u1ec9 kh\u1ed1i gi\u1eefa kh\u00ed A v\u00e0 kh\u00ed B<\/p>\n\n\n\n
2\/ C\u00e1ch x\u00e1c \u0111\u1ecbnh kh\u00ed A nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed bao nhi\u00eau l\u1ea7n, c\u00f4ng th\u1ee9c t\u1ec9 kh\u1ed1i gi\u1eefa kh\u00ed A v\u00e0 kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
3\/ C\u00e1c c\u00f4ng th\u1ee9c t\u00ednh t\u1ec9 kh\u1ed1i li\u00ean quan<\/p>\n\n\n\n
S\u01a1 \u0111\u1ed3 t\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed<\/p>\n\n\n\n
\u0110\u0103ng ky\u0301 ho\u0323c th\u01b0\u0309 mi\u00ea\u0303n phi\u0301 m\u00f4n Ho\u0301a ho\u0323c t\u01b0\u0300 l\u01a1\u0301p 8 \u0111\u00ea\u0301n l\u01a1\u0301p 12<\/p><\/blockquote>\n\n\n\n
C\u00e1c d\u1ea1ng b\u00e0i t\u1eadp hay g\u1eb7p<\/p>\n\n\n\n
D\u1ea1ng 1: X\u00e1c \u0111\u1ecbnh t\u1ec9 kh\u1ed1i h\u1ed7n h\u1ee3p kh\u00ed<\/p>\n\n\n\n
M\u1ed9t v\u00e0i l\u01b0u \u00fd c\u1ea7n nh\u1edb:<\/p>\n\n\n\n
B\u01b0\u1edbc 1: Trong h\u1ed7n h\u1ee3p kh\u00ed t\u00ednh kh\u1ed1i l\u01b0\u1ee3ng mol trung b\u00ecnh<\/p>\n\n\n\n
B\u01b0\u1edbc 2: X\u00e1c \u0111\u1ecbnh t\u1ec9 kh\u1ed1i h\u1ed7n h\u1ee3p kh\u00ed<\/p>\n\n\n\n
V\u00ed d\u1ee5 1: T\u1ec9 kh\u1ed1i h\u1ed7n h\u1ee3p ch\u1ee9a 7g kh\u00ed etilen (C2H4) v\u00e0 4g kh\u00ed metan (CH4) so v\u1edbi kh\u00f4ng kh\u00ed l\u00e0 bao nhi\u00eau?<\/p>\n\n\n\n
H\u01b0\u1edbng d\u1eabn:<\/p>\n\n\n\n
S\u1ed1 mol c\u1ee7a CH4 l\u00e0:<\/p>\n\n\n\n
S\u1ed1 mol c\u1ee7a C2H4 l\u00e0:<\/p>\n\n\n\n
Suy ra h\u1ed7n h\u1ee3p kh\u00ed c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng trung b\u00ecnh l\u00e0:<\/p>\n\n\n\n
Kh\u1ed1i l\u01b0\u1ee3ng trung b\u00ecnh h\u1ed7n h\u1ee3p kh\u00ed<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i h\u1ed7n h\u1ee3p v\u00e0 kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
V\u00ed d\u1ee5 2: M\u1ed9t h\u1ed7n h\u1ee3p X g\u1ed3m O2 v\u00e0 H2 (\u0111i\u1ec1u ki\u1ec7n kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng x\u1ea3y ra), h\u1ed7n h\u1ee3p c\u00f3 t\u1ec9 kh\u1ed1i \u0111\u1ed1i v\u1edbi kh\u00f4ng kh\u00ed l\u00e0 0,3276. T\u00ednh ph\u1ea7n tr\u0103m theo s\u1ed1 mol c\u1ee7a H2 trong h\u1ed7n h\u1ee3p.<\/p>\n\n\n\n
H\u01b0\u1edbng d\u1eabn:<\/p>\n\n\n\n
G\u1ecdi s\u1ed1 mol c\u1ee7a kh\u00ed H2 v\u00e0 O2 trong h\u1ed7n h\u1ee3p X l\u1ea7n l\u01b0\u1ee3t l\u00e0 x (mol) v\u00e0 y (mol)<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a h\u1ed7n h\u1ee3p X so v\u1edbi kh\u00f4ng kh\u00ed l\u00e0:<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i c\u1ee7a h\u1ed7n h\u1ee3p X so v\u1edbi kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
Kh\u1ed1i l\u01b0\u1ee3ng trung b\u00ecnh h\u1ed7n h\u1ee3p<\/p>\n\n\n\n
Suy ra 2x + 32y = 9,5x + 9,5y Suy ra 7,5x = 22,5 => x = 3y<\/p>\n\n\n\n
% s\u1ed1 mol kh\u00ed H2 l\u00e0:<\/p>\n\n\n\n
% s\u1ed1 mol kh\u00ed hidro (H2)<\/p>\n\n\n\n
V\u00ed d\u1ee5 3: T\u00ednh t\u1ec9 kh\u1ed1i h\u1ed7n h\u1ee3p c\u00f3 ch\u1ee9a kh\u00ed N2 v\u00e0 kh\u00ed O3 c\u00f3 t\u1ec9 l\u1ec7 t\u01b0\u01a1ng \u1ee9ng l\u00e0 1 : 2 so v\u1edbi kh\u00f4ng kh\u00ed.<\/p>\n\n\n\n
H\u01b0\u1edbng d\u1eabn:<\/p>\n\n\n\n
G\u1ecdi s\u1ed1 mol c\u1ee7a kh\u00ed N2 l\u00e0 a mol suy ra s\u1ed1 mol c\u1ee7a kh\u00ed O3 l\u00e0 2a mol<\/p>\n\n\n\n
H\u1ed7n h\u1ee3p kh\u00ed c\u1ea7n t\u00ecm c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng trung b\u00ecnh l\u00e0:<\/p>\n\n\n\n
Kh\u1ed1i l\u01b0\u1ee3ng trung b\u00ecnh h\u1ed7n h\u1ee3p kh\u00ed c\u1ea7n t\u00ecm<\/p>\n\n\n\n
Suy ra t\u1ec9 kh\u1ed1i h\u1ed7n h\u1ee3p tr\u00ean so v\u1edbi kh\u00f4ng kh\u00ed l\u00e0:<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i gi\u1eefa h\u1ed7n h\u1ee3p v\u00e0 kh\u00f4ng kh\u00ed<\/p>\n\n\n\n
D\u1ea1ng 2: T\u00ednh t\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed<\/p>\n\n\n\n
M\u1ed9t v\u00e0i l\u01b0u \u00fd c\u1ea7n nh\u1edb:<\/p>\n\n\n\n
L\u01b0u \u00fd c\u00f4ng th\u1ee9c t\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed<\/p>\n\n\n\n
V\u00ed d\u1ee5 1: T\u1ec9 kh\u1ed1i c\u1ee7a kh\u00ed A \u0111\u1ed1i v\u1edbi kh\u00ed B l\u00e0 2,125 v\u00e0 t\u1ec9 kh\u1ed1i kh\u00ed B \u0111\u1ed1i v\u1edbi oxi l\u00e0 0,5. T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a kh\u00ed A.<\/p>\n\n\n\n
H\u01b0\u1edbng d\u1eabn:<\/p>\n\n\n\n
Ta c\u00f3:<\/p>\n\n\n\n
Suy ra MB = 32 x 0,5 = 16<\/p>\n\n\n\n
M\u1eb7t kh\u00e1c:<\/p>\n\n\n\n
Suy ra MA = 2,125 x 16 = 34<\/p>\n\n\n\n
K\u1ebft lu\u1eadn: kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a kh\u00ed A l\u00e0 34 g\/mol<\/p>\n\n\n\n
B\u00e2\u0323t mi\u0301 ca\u0301ch \u0111a\u0301nh bay n\u00f4\u0303i s\u01a1\u0323 m\u00f4n Ho\u0301a ho\u0323c \u2013 Vietlearn<\/p><\/blockquote>\n\n\n\n
V\u00ed d\u1ee5 2: Kh\u00ed X2 c\u00f3 t\u1ec9 kh\u1ed1i so v\u1edbi kh\u00ed axetilen (C2H2) l\u00e0 2,731 g\/mol. T\u00ecm kh\u00ed X2<\/p>\n\n\n\n
H\u01b0\u1edbng d\u1eabn:<\/p>\n\n\n\n
\u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c t\u1ec9 kh\u1ed1i<\/p>\n\n\n\n
M\u00e0 = 2 x MX = 71 suy ra MX = 35,5<\/p>\n\n\n\n
V\u1eady kh\u00ed c\u1ea7n t\u00ecm l\u00e0 kh\u00ed Cl2<\/p>\n\n\n\n
V\u00ed d\u1ee5 3: Kh\u00ed A c\u00f3 d\u1ea1ng c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed l\u00e0 RO2, t\u1ec9 kh\u1ed1i kh\u00ed A so v\u1edbi H2 l\u00e0 32. T\u00ecm c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a kh\u00ed A.<\/p>\n\n\n\n
H\u01b0\u1edbng d\u1eabn:<\/p>\n\n\n\n
Theo \u0111\u1ea7u b\u00e0i ta c\u00f3: t\u1ec9 kh\u1ed1i kh\u00ed A so v\u1edbi H2 l\u00e0 32<\/p>\n\n\n\n
T\u1ec9 kh\u1ed1i kh\u00ed A so v\u1edbi H2 l\u00e0 32<\/p>\n\n\n\n
A c\u00f3 c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed d\u1ea1ng RO2 suy ra M = MR + 2.MO = 64<\/p>\n\n\n\n
=> MR = 64 \u2013 2.16 = 32 v\u1eady R l\u00e0 nguy\u00ean t\u1ed1 S<\/p>\n\n\n\n
K\u1ebft lu\u1eadn: c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a kh\u00ed A l\u00e0 SO2<\/p>\n\n\n\n
B\u00e0i vi\u1ebft tr\u00ean \u0111\u00e2y \u0111\u00e3 cung c\u1ea5p cho b\u1ea1n \u0111\u1ecdc nh\u1eefng ki\u1ebfn th\u1ee9c c\u01a1 b\u1ea3n<\/a> v\u1ec1 t\u1ec9 kh\u1ed1i c\u1ee7a ch\u1ea5t kh\u00ed, c\u00f4ng th\u1ee9c t\u00ednh c\u00f9ng c\u00e1c d\u1ea1ng b\u00e0i t\u1eadp hay g\u1eb7p. Hy v\u1ecdng b\u00e0i vi\u1ebft c\u1ee7a ch\u00fang t\u00f4i s\u1ebd gi\u00fap b\u1ea1n h\u1ecdc t\u1eadp<\/a> v\u00e0 nghi\u00ean c\u1ee9u \u0111\u01b0\u1ee3c nhi\u1ec1u ki\u1ebfn th\u1ee9c. Ch\u00fac b\u1ea1n th\u00e0nh c\u00f4ng!<\/p>\n\n\n\n
<\/p>\n\n\n\n
Mol h\u00f3a 8 : T\u1ed5ng h\u1ee3p c\u00e1c d\u1ea1ng b\u00e0i t\u1eadp v\u00e0 l\u1eddi gi\u1ea3i<\/p>\n\n\n\n
Chuy\u1ec3n \u0111\u1ed5i gi\u1eefa kh\u1ed1i l\u01b0\u1ee3ng, th\u1ec3 t\u00edch v\u00e0 ch\u1ea5<\/p>\n\n\n\n\n\n\n","protected":false},"excerpt":{"rendered":"
Ghi ch\u00fa: T\u00e0i li\u1ec7u tr\u00edch d\u1eabn L\u00e0m sao \u0111\u1ec3 bi\u1ebft \u0111\u01b0\u1ee3c ch\u1ea5t kh\u00ed n\u00e0o \u0111\u00f3 c\u00f3 nh\u1eefng t\u00ednh ch\u1ea5t g\u00ec? L\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 ch\u00fang ta bi\u1ebft \u0111\u01b0\u1ee3c ch\u1ea5t kh\u00ed \u0111\u00f3 nh\u1eb9 hay n\u1eb7ng h\u01a1n kh\u00ed Hidro H2, kh\u00ed Oxi O2 hay kh\u00f4ng kh\u00ed. V\u1eady c\u00e2u h\u1ecfi \u0111\u1eb7t ra l\u00e0: T\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed l\u00e0 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_disable_autopaging":false},"categories":[8],"tags":[],"class_list":["post-776","post","type-post","status-publish","format-standard","hentry","category-hoa-hoc"],"_links":{"self":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/776","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/comments?post=776"}],"version-history":[{"count":0,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/posts\/776\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/media?parent=776"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/categories?post=776"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vietlearn.org\/kien-thuc\/wp-json\/wp\/v2\/tags?post=776"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}